Create Maximize_Toys.cpp

Maximize_Toys.cpp

@@ -0,0 +1,81 @@
+// PS:
+//  Given an array consisting of the cost of toys.
+// Given an integer K depicting the amount of money available to purchase toys.
+//  Write a program to find the maximum number of toys one can buy with the amount K.
+
+#include <cmath>
+#include <cstdio>
+#include <vector>
+#include <iostream>
+#include <algorithm>
+#include <bits/stdc++.h>
+using namespace std;
+#define ll long long int
+#define lt long long
+#define pi (3.141592653589)
+#define mod 1000000007
+
+#define tc    \
+    int t;    \
+    cin >> t; \
+    while (t--)
+
+#define lull NULL
+
+#define float double
+
+#define pb push_back
+
+#define mp make_pair
+
+#define ff first
+
+#define ss second
+
+#define all(c) c.begin(), c.end()
+
+#define min3(a, b, c) min(c, min(a, b))
+
+#define min4(a, b, c, d) min(d, min(c, min(a, b)))
+
+#define fir(i, n) for (int i = n - 1; i >= 0; i--)
+
+#define fi(i, n) for (int i = 0; i < n; i++)
+#define fin(j, n) for (int i = j; i <= n; i++)
+
+#define fast ios_base::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
+
+// This functions returns the required number of toys
+int maximum_toys(vector<int> &cost, int N, int K)
+{
+    int count = 0, sum = 0;
+
+    // sort the cost array
+    sort(cost.begin(), cost.end());
+    for (int i = 0; i < N; i++)
+    {
+
+        // Check if we can buy ith toy or not
+        if (sum + cost[i] <= K)
+        {
+            sum = sum + cost[i];
+            // Increment count
+            count++;
+        }
+    }
+    return count;
+}
+
+int main()
+{
+    int k, n;
+    cin >> n >> k;
+
+    vector<int> arr(n);
+    fi(i, n)
+    {
+        cin >> arr[i];
+    }
+    cout << maximum_toys(arr, n, k) << endl;
+    return 0;
+}