Fix qt6 compatibility in test

(cherry picked from commit 0ead32e)
qgis · Nov 25, 2024 · 2b7499f · 2b7499f
1 parent c15b362
commit 2b7499f
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Showing 3 changed files with 6 additions and 6 deletions.
diff --git a/tests/src/python/test_qgscategorizedsymbolrenderer.py b/tests/src/python/test_qgscategorizedsymbolrenderer.py
@@ -939,8 +939,8 @@ def test_to_sld(self):
         # this category should NOT be included in the SLD, as it would otherwise result
         # in an invalid se:rule with no symbolizer element
         symbol_which_is_empty_in_sld = createFillSymbol()
-        symbol_which_is_empty_in_sld[0].setBrushStyle(Qt.NoBrush)
-        symbol_which_is_empty_in_sld[0].setStrokeStyle(Qt.NoPen)
+        symbol_which_is_empty_in_sld[0].setBrushStyle(Qt.BrushStyle.NoBrush)
+        symbol_which_is_empty_in_sld[0].setStrokeStyle(Qt.PenStyle.NoPen)
         renderer.addCategory(QgsRendererCategory(None, symbol_which_is_empty_in_sld, 'empty', True, '4'))
 
         dom = QDomDocument()

diff --git a/tests/src/python/test_qgsgraduatedsymbolrenderer.py b/tests/src/python/test_qgsgraduatedsymbolrenderer.py
@@ -586,8 +586,8 @@ def test_to_sld(self):
         # this category should NOT be included in the SLD, as it would otherwise result
         # in an invalid se:rule with no symbolizer element
         symbol_which_is_empty_in_sld = createFillSymbol()
-        symbol_which_is_empty_in_sld[0].setBrushStyle(Qt.NoBrush)
-        symbol_which_is_empty_in_sld[0].setStrokeStyle(Qt.NoPen)
+        symbol_which_is_empty_in_sld[0].setBrushStyle(Qt.BrushStyle.NoBrush)
+        symbol_which_is_empty_in_sld[0].setStrokeStyle(Qt.PenStyle.NoPen)
         renderer.addClassRange(
             QgsRendererRange(25.5, 26.5, symbol_which_is_empty_in_sld, 'd', False, '2'))
 

diff --git a/tests/src/python/test_qgsrulebasedrenderer.py b/tests/src/python/test_qgsrulebasedrenderer.py
@@ -55,8 +55,8 @@ def test_to_sld(self):
         # this rule should NOT be included in the SLD, as it would otherwise result
         # in an invalid se:rule with no symbolizer element
         symbol_which_is_empty_in_sld = createFillSymbol()
-        symbol_which_is_empty_in_sld[0].setBrushStyle(Qt.NoBrush)
-        symbol_which_is_empty_in_sld[0].setStrokeStyle(Qt.NoPen)
+        symbol_which_is_empty_in_sld[0].setBrushStyle(Qt.BrushStyle.NoBrush)
+        symbol_which_is_empty_in_sld[0].setStrokeStyle(Qt.PenStyle.NoPen)
         root_rule.appendChild(
             QgsRuleBasedRenderer.Rule(symbol_which_is_empty_in_sld, filterExp='"something"=3', label="label c", description="rule c"))