This project showcases a buck converter circuit designed using the TLC555 timer IC and the IRF3708 MOSFET. The circuit efficiently steps down voltage from 24V to 5V while maintaining a maximum current of 1A, resulting in a power output of 24W. Below you will find the schematic, component list, and information about the students involved in this project.
A buck converter is a DC-DC power converter that steps down voltage from its input to its output. This design leverages the TLC555 as a PWM generator to drive the switching of the IRF3708 MOSFET, enabling efficient voltage conversion from 24V to 5V.
- Input Voltage: 24V
- Input Current: Max 1A (24W)
- Output Voltage: 5V
- Output Power: Max 5W
The schematic above shows the key components:
- TLC555: Timer IC used to generate the pulse-width modulation (PWM) signal.
- IRF3708: N-channel MOSFET used as the main switching device.
- Other passive components (capacitors, inductors, resistors) are used to filter the output and ensure stable voltage regulation.
- TLC555 Timer IC
- IRF3708 N-channel MOSFET
- Inductor
- Capacitors
- Diodes
- Resistors
- The TLC555 generates a PWM signal, which controls the duty cycle of the MOSFET.
- The IRF3708 MOSFET acts as the switch in the buck converter, toggling between on and off states based on the PWM signal.
- The inductor and capacitor filter the output, converting the PWM signal into a stable 5V DC output from the 24V input.
Shashank Naik 60002220111
Yash Doke 60002220058
Mihir Sanghvi 60002230125
Om Kulkarni 60002231053
- Assemble the circuit as per the schematic.
- Connect the 24V input voltage (ensure it does not exceed 1A).
- Observe the 5V output voltage, which is designed to supply up to 1A.
This project is licensed under the MIT License - see the LICENSE file for details.