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茹靖涵 level 1 已完成 #19
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茹靖涵 level 1 已完成 #19
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#include <iostream> | ||
#include <windows.h> | ||
#include <stdlib.h> | ||
using namespace std; | ||
int main() { | ||
HANDLE hOut; | ||
CONSOLE_SCREEN_BUFFER_INFO a; | ||
hOut = GetStdHandle(STD_OUTPUT_HANDLE); | ||
GetConsoleScreenBufferInfo(hOut, &a); | ||
int length_of_console = a.dwSize.X; | ||
int flag = 0; // symbolize whether 'a' has reached the two sides | ||
while(1){ | ||
for(int i=0;i<length_of_console;i++){ | ||
for (int j=0;j<i;j++)cout << " "; | ||
cout << "A"; | ||
Sleep(30); | ||
if (i == length_of_console - 1) flag = 1; // so that 'a' could turn left | ||
if (i == 0) flag = 0; | ||
if (flag) i -= 2; | ||
system("cls"); | ||
} | ||
} | ||
system("pause"); | ||
return 0; | ||
} | ||
|
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#include <iostream> | ||
#include<cstdio> | ||
using namespace std; | ||
bool isPrime(int x){ // simple version | ||
if (x == 1) return false; | ||
for(int i = 2; i * i <= x; i++) if (x % i == 0) return false; | ||
return true; | ||
} | ||
int main() { | ||
int n; | ||
cin >> n; | ||
bool ans = isPrime(n); | ||
if (ans) printf("%d is a prime.\n",n); | ||
else printf("%d is not a prime.\n",n); | ||
system("pause"); | ||
return 0; | ||
} |
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#include <iostream> | ||
using namespace std; | ||
const int lifetime = 84; // His lifetime could be divided by 12 and 7,so by common sense,his lifetime is 84. | ||
const int childhood = 14; | ||
const int youth = 7; | ||
const int bachelor = 12; | ||
const int marriage = 5; | ||
int main() { | ||
int father = childhood + youth + bachelor + marriage; | ||
int son = 0; | ||
int time = lifetime - 4 - father; | ||
if (time == lifetime / 2) cout << 80 << endl; | ||
return 0; | ||
} |
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#include <iostream> | ||
using namespace std; | ||
const int max_lifetime = 800; // the life span of the legendary "PengZu" | ||
int main() { | ||
for(int i=0;i<max_lifetime;i++){ // i is the lifetime of Diophantus | ||
if(i % 6 != 0 || i % 12 != 0 || i%7 != 0) continue; | ||
int childhood = i / 6; | ||
int youth = i / 12; | ||
int bachelor = i / 7; | ||
int marriage = 5; | ||
int father = childhood + youth + bachelor + marriage; | ||
int son = 0; | ||
for(int j = 1;j <= i-father;j++){ | ||
if(son == i/2 && father + son + 4 == i) { | ||
cout << i << endl; | ||
break; | ||
} else son++; | ||
} | ||
} | ||
system("pause"); | ||
return 0; | ||
} |
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#include <iostream> | ||
using namespace std; | ||
int digit[5]; // record every digit of the number | ||
int main() { | ||
for(int i = 100;i < 1000;i++){ | ||
int tmp = i; | ||
for(int j = 1;j <= 3;j++){ | ||
digit[j] = tmp % 10; | ||
tmp /= 10; | ||
} | ||
int i0 = digit[1] * digit[1] * digit[1]; | ||
int i1 = digit[2] * digit[2] * digit[2]; | ||
int i2 = digit[3] * digit[3] * digit[3]; | ||
if(i == i0 + i1 + i2) cout << i << endl; | ||
} | ||
return 0; | ||
} |
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#include <iostream> | ||
#include <time.h> | ||
using namespace std; | ||
int isPrime(int n){ // ordinary algorithm | ||
if(n == 1) return 0; | ||
for (int i = 2;i * i <= n;i++){ | ||
if (n % i == 0) return 0; | ||
} | ||
return 1; | ||
} | ||
int main() { | ||
int begintime,endtime; | ||
begintime = clock(); | ||
for(int i = 2;i <= 1000;i++){ | ||
if(isPrime(i)) cout << i << ' '; | ||
} | ||
endtime = clock(); | ||
cout << "Runtime is " << endtime - begintime << "ms" << endl; | ||
return 0; | ||
} |
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#include <stdio.h> | ||
#include <time.h> | ||
int main() { | ||
int begintime,endtime; | ||
begintime = clock(); | ||
printf("2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 1\n" | ||
"63 167 173 179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 271 277 281 283 293 307 311 313 317 331 3\n" | ||
"37 347 349 353 359 367 373 379 383 389 397 401 409 419 421 431 433 439 443 449 457 461 463 467 479 487 491 499 503 509 5\n" | ||
"21 523 541 547 557 563 569 571 577 587 593 599 601 607 613 617 619 631 641 643 647 653 659 661 673 677 683 691 701 709 7\n" | ||
"19 727 733 739 743 751 757 761 769 773 787 797 809 811 821 823 827 829 839 853 857 859 863 877 881 883 887 907 911 919 9\n" | ||
"29 937 941 947 953 967 971 977 983 991 997"); // Apparently this is the most efficient algorithm | ||
endtime = clock(); | ||
printf("Runtime is %dms",endtime - begintime); | ||
return 0; | ||
} |
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#include <iostream> | ||
#include <string.h> | ||
#include <time.h> | ||
using namespace std; | ||
int main() { // Use"ShaiFa" | ||
int begintime,endtime; | ||
begintime = clock(); | ||
int f[1005]; // identify whether the number is a prime | ||
memset(f,1,sizeof f); | ||
for(int i = 2;i < 1000;i++){ | ||
if(f[i]) | ||
for(int j = 2; j * i <= 1000; j++) f[i*j] = 0; | ||
} | ||
for(int i = 2;i < 1000;i++) if (f[i]) cout << i << ' '; | ||
endtime = clock(); | ||
cout << "Runtime is " << endtime - begintime << "ms" << endl; | ||
return 0; | ||
} |
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#include <iostream> | ||
#include <stdio.h> | ||
using namespace std; | ||
int isPrime(int x){ | ||
for (int i = 2; i * i <= x; i++){ | ||
if (x % i == 0) return 0; | ||
} | ||
return 1; | ||
} | ||
int main() { | ||
int prime[30]; | ||
int cnt = 0; | ||
for (int n = 2; n < 100; n++){ | ||
if(isPrime(n)) prime[++cnt] = n; | ||
} | ||
for(int x = 4 ; x <= 100; x += 2){ | ||
for(int i = 1; i <= cnt; i++){ | ||
if (isPrime(x - prime[i])){ // could use binary search in prime[] to optimize | ||
printf("%d = %d + %d\n",x,prime[i],x-prime[i]); | ||
break; | ||
} | ||
} | ||
} | ||
system("pause"); | ||
return 0; | ||
} |
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#include <iostream> | ||
#include <string> | ||
using namespace std; | ||
string a; | ||
char b[1000005]; | ||
void encrypt(string s) { | ||
for (int i = 0; i < s.length(); i++){ | ||
b[i] = s[i] + 3; | ||
cout << b[i]; | ||
} | ||
cout << endl; | ||
} | ||
void decrept(){ | ||
for (int i = 0; i < a.length(); i++){ | ||
char tmp = b[i] - 3; | ||
cout << tmp; | ||
} | ||
cout << endl; | ||
} | ||
int main() { | ||
cin >> a; | ||
encrypt(a); | ||
decrept(); | ||
system("pause"); | ||
return 0; | ||
} | ||
|
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#include <iostream> | ||
#include <cstdio> | ||
#include <stack> | ||
using namespace std; | ||
int n; | ||
stack<int> a,b,c; | ||
|
||
void output(int n, int x, char a, char b){ | ||
printf("%d : %d from %c to %c\n",n,x,a,b); | ||
} | ||
|
||
char get_top(char x){ | ||
int tmp; | ||
if(x == 'a'){ | ||
tmp = a.top(); | ||
} else if(x == 'b'){ | ||
tmp = b.top(); | ||
} else{ | ||
tmp = c.top(); | ||
} | ||
return tmp; | ||
} | ||
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||
void reverse(char x, char y){ | ||
int tmp; | ||
if(x == 'a' && y == 'b'){ | ||
tmp = a.top(); | ||
a.pop(); | ||
b.push(tmp); | ||
}else if(x == 'a' && y == 'c'){ | ||
tmp = a.top(); | ||
a.pop(); | ||
c.push(tmp); | ||
}else if(x == 'b' && y == 'a'){ | ||
tmp = b.top(); | ||
b.pop(); | ||
a.push(tmp); | ||
}else if(x == 'b' && y == 'c'){ | ||
tmp = b.top(); | ||
b.pop(); | ||
c.push(tmp); | ||
}else if(x == 'c' && y == 'a'){ | ||
tmp = c.top(); | ||
c.pop(); | ||
a.push(tmp); | ||
}else if(x == 'c' && y == 'b'){ | ||
tmp = c.top(); | ||
c.pop(); | ||
b.push(tmp); | ||
} | ||
} | ||
|
||
void solve(int n, char x, char y, char z){ | ||
if(n == 1){ | ||
output(n,get_top(x),x,z); | ||
reverse(x,z); | ||
return; | ||
} | ||
solve(n-1, x,z,y); | ||
output(n,get_top(x),x,z); | ||
reverse(x,z); | ||
solve(n-1,y,x,z); | ||
} | ||
int main(){ | ||
char x = 'a',y = 'b',z = 'c'; | ||
cin >> n; | ||
for(int i = n; i >= 1; i --){ | ||
a.push(i); | ||
} | ||
solve(n,x,y,z);// | ||
system("pause"); | ||
return 0; | ||
} |
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其实ans这个中间变量可以去掉,读起来反而更自然