Queue shouldn't require Copy

By requiring items to be `Copy` we reduce the queue to only work with
primitives. But, queue dosn't require `Copy` to send items. Yes, they
are technically copied over to the Queue buffer, but semantically this
is a move, and having `send()` consume it's argument provides the move
semantics.

freertos-rust/src/queue.rs

@@ -4,18 +4,17 @@ use crate::prelude::v1::*;
 use crate::shim::*;
 use crate::units::*;
 
-unsafe impl<T: Sized + Copy> Send for Queue<T> {}
-unsafe impl<T: Sized + Copy> Sync for Queue<T> {}
+unsafe impl<T: Sized> Send for Queue<T> {}
+unsafe impl<T: Sized> Sync for Queue<T> {}
 
-/// A queue with a finite size. The items are owned by the queue and are
-/// copied.
+/// A queue with a finite size.
 #[derive(Debug)]
-pub struct Queue<T: Sized + Copy> {
+pub struct Queue<T: Sized> {
     queue: FreeRtosQueueHandle,
     item_type: PhantomData<T>,
 }
 
-impl<T: Sized + Copy> Queue<T> {
+impl<T: Sized> Queue<T> {
     pub fn new(max_size: usize) -> Result<Queue<T>, FreeRtosError> {
         let item_size = mem::size_of::<T>();
 
@@ -107,7 +106,7 @@ impl<T: Sized + Copy> Queue<T> {
     }
 }
 
-impl<T: Sized + Copy> Drop for Queue<T> {
+impl<T: Sized> Drop for Queue<T> {
     fn drop(&mut self) {
         unsafe {
             freertos_rs_queue_delete(self.queue);