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group02/1554421063/src/com/github/FelixCJF/coding2017/coderising/array/ArrayUtil.java
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package com.github.FelixCJF.coding2017.coderising.array; | ||
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import java.util.ArrayList; | ||
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public class ArrayUtil { | ||
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/** | ||
* 给定一个整形数组a , 对该数组的值进行置换 | ||
例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7] | ||
如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7] | ||
* @param origin | ||
* @return | ||
*/ | ||
public void reverseArray(int[] origin){ | ||
int array[] = new int[origin.length]; | ||
for (int i = 0; i<origin.length; i++) { | ||
array[i] = origin[origin.length - 1 - i]; | ||
} | ||
System.arraycopy(array, 0, origin, 0, origin.length); | ||
} | ||
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/** | ||
* 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} | ||
* 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为: | ||
* {1,3,4,5,6,6,5,4,7,6,7,5} | ||
* @param oldArray | ||
* @return | ||
*/ | ||
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public int[] removeZero(int[] oldArray){ | ||
int zero = 0; | ||
//统计原来数组0的个数 | ||
for (int i = 0; i < oldArray.length; i++) { | ||
if (oldArray[i] == 0) { | ||
zero ++; | ||
} | ||
} | ||
int[] newArr = new int[oldArray.length - zero]; | ||
int count = 0; | ||
for (int i = 0; i<oldArray.length; i ++) { | ||
if (oldArray[i] != 0) { | ||
newArr[count] = oldArray[i]; | ||
count ++; | ||
} | ||
} | ||
return newArr; | ||
} | ||
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/** | ||
* 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的 | ||
* 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复 | ||
* @param array1 | ||
* @param array2 | ||
* @return | ||
*/ | ||
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public int[] merge(int[] array1, int[] array2){ | ||
//创建新数组 | ||
int length1 = array1.length; | ||
int length2 = array2.length; | ||
int length = length1 + length2; | ||
int[] newArr = new int[length]; | ||
//插入 | ||
for (int i = 0; i < length1; i++) { | ||
newArr[i] = array1[i]; | ||
} | ||
for (int i = 0; i < length2; i++) { | ||
newArr[length1 - 1 + i] = array2[i]; | ||
} | ||
//排序 | ||
for (int i = 0; i < length-1; i ++){ | ||
if (newArr[i] > newArr[i+1]) { | ||
int temp = newArr[i]; | ||
newArr[i] = newArr[i+1]; | ||
newArr[i + 1] = temp; | ||
} | ||
} | ||
return newArr; | ||
} | ||
/** | ||
* 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size | ||
* 注意,老数组的元素在新数组中需要保持 | ||
* 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为 | ||
* [2,3,6,0,0,0] | ||
* @param oldArray | ||
* @param size | ||
* @return | ||
*/ | ||
public int[] grow(int [] oldArray, int size){ | ||
int newArr[] = new int[oldArray.length + size]; | ||
System.arraycopy(oldArray, 0, newArr, 0, oldArray.length); | ||
return newArr; | ||
} | ||
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/** | ||
* 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列 | ||
* 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13] | ||
* max = 1, 则返回空数组 [] | ||
* @param max | ||
* @return | ||
*/ | ||
public int[] fibonacci(int max){ | ||
int[] newArr; | ||
int f1 = 0; | ||
int f2 = 1; | ||
int f = 0; | ||
if (max < 2) { | ||
return newArr = new int[0]; | ||
} | ||
ArrayList list = new ArrayList(); | ||
for (int i = 2; f < max; i++) { | ||
list.add(f2); | ||
f = f1 + f2; | ||
f1 = f2; | ||
f2 = f; | ||
} | ||
newArr = new int[list.size()]; | ||
for (int i = 0; i < newArr.length; i++) { | ||
newArr[i] = (int) list.get(i); | ||
} | ||
return newArr; | ||
} | ||
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/** | ||
* 返回小于给定最大值max的所有素数数组 | ||
* 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19] | ||
* @param max | ||
* @return | ||
*/ | ||
public int[] getPrimes(int max){ | ||
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ArrayList list = new ArrayList(); | ||
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for (int i = 1; i < max; i++) { | ||
if (isPrime(i)) { | ||
list.add(i); | ||
} | ||
} | ||
int[] newArr = new int[list.size()]; | ||
for (int i = 0; i < newArr.length; i++) { | ||
newArr[i] = (int) list.get(i); | ||
} | ||
return newArr; | ||
} | ||
//判断是否为素数 | ||
private boolean isPrime(int a) { | ||
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boolean flag = true; | ||
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if (a < 2) {// 素数不小于2 | ||
return false; | ||
} else { | ||
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for (int i = 2; i <= Math.sqrt(a); i++) { | ||
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if (a % i == 0) {// 若能被整除,则说明不是素数,返回false | ||
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flag = false; | ||
break;// 跳出循环 | ||
} | ||
} | ||
} | ||
return flag; | ||
} | ||
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/** | ||
* 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3 | ||
* 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数 | ||
* @param max | ||
* @return | ||
*/ | ||
public int[] getPerfectNumbers(int max){ | ||
int[] newArr; | ||
if (max == 0) { | ||
return newArr = new int[0]; | ||
} | ||
ArrayList list = new ArrayList(); | ||
for (int i = 1; i < max; i++) { | ||
if (isWanshu(i)) { | ||
list.add(i); | ||
} | ||
} | ||
newArr = new int[list.size()]; | ||
for (int i = 0; i < newArr.length; i++) { | ||
newArr[i] = (int) list.get(i); | ||
} | ||
return newArr; | ||
} | ||
//判断一个数是不是完数 | ||
private boolean isWanshu(int n) | ||
{ | ||
boolean flag=false; | ||
int i,sum=0; | ||
for(i=1;i<=n/2;i++) | ||
{ | ||
if(n%i==0) | ||
{ | ||
sum+=i; | ||
} | ||
} | ||
if(sum==n) | ||
{ | ||
flag=true; | ||
} | ||
return flag; | ||
} | ||
/** | ||
* 用seperator 把数组 array给连接起来 | ||
* 例如array= [3,8,9], seperator = "-" | ||
* 则返回值为"3-8-9" | ||
* @param array | ||
* @param s | ||
* @return | ||
*/ | ||
public String join(int[] array, String seperator){ | ||
String string = ""; | ||
for (int i = 0; i < array.length; i++) { | ||
if (i == array.length - 1) { | ||
string += array[i]; | ||
} else { | ||
string += array[i] + seperator; | ||
} | ||
} | ||
return string; | ||
} | ||
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} |
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...02/1554421063/src/com/github/FelixCJF/coding2017/coderising/array/test/ArrayUtilTest.java
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package com.github.FelixCJF.coding2017.coderising.array.test; | ||
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import static org.junit.Assert.*; | ||
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import org.junit.Before; | ||
import org.junit.Rule; | ||
import org.junit.Test; | ||
import org.junit.rules.ExpectedException; | ||
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import com.github.FelixCJF.coding2017.coderising.array.ArrayUtil; | ||
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public class ArrayUtilTest | ||
{ | ||
private ArrayUtil myArray; | ||
@Before | ||
public void setUp() throws Exception | ||
{ | ||
myArray = new ArrayUtil(); | ||
} | ||
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@Test | ||
public void testReverseArray() | ||
{ | ||
int[] a = {1, 2, 1, 3, 5, 6}; | ||
int[] b = {6, 5, 3, 1, 2, 1}; | ||
int[] c = new int[0]; | ||
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myArray.reverseArray(a); | ||
assertArrayEquals(a, b); | ||
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//对空数组进行反转 | ||
myArray.reverseArray(c); | ||
assertArrayEquals(c, new int[0]); | ||
} | ||
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@Test | ||
public void testRemoveZero() | ||
{ | ||
int[] oldArr= {1, 3, 4, 5, 0, 0, 6, 6, 0, 5, 4, 7, 6, 7, 1, 2, 0, 5}; | ||
int b[] = {1, 3, 4, 5, 6, 6, 5, 4, 7, 6, 7, 1, 2, 5}; | ||
int[] c = myArray.removeZero(oldArr); | ||
assertArrayEquals(b, c); | ||
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int[] d = new int[0]; | ||
assertArrayEquals(d, new int[0]); | ||
} | ||
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@Test | ||
public void testMerge() | ||
{ | ||
int a1[] = {1, 2, 3, 4, 5}; | ||
int b1[] = {3, 4, 5, 6, 7, 8}; | ||
int c1[] = {1, 2, 3, 4, 5, 6, 7, 8}; | ||
int[] newArray1 = myArray.merge(a1, b1); | ||
assertArrayEquals(c1, newArray1); | ||
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int a2[] = new int[0]; | ||
int b2[] = {0, 2, 3, 6, 7, 8}; | ||
int c2[] = {0, 2, 3, 6, 7, 8}; | ||
int[] newArray2 = myArray.merge(a2, b2); | ||
assertArrayEquals(c2, newArray2); | ||
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int a3[] = {0, 2, 3, 6, 7, 8}; | ||
int b3[] = new int[0]; | ||
int c3[] = {0, 2, 3, 6, 7, 8}; | ||
int[] newArray3 = myArray.merge(a3, b3); | ||
assertArrayEquals(c3, newArray3); | ||
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int[] a4 = new int[0]; | ||
int[] b4 = new int[0]; | ||
int[] newArray4 = myArray.merge(a4, b4); | ||
assertArrayEquals(new int[0], newArray4); | ||
} | ||
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@Rule | ||
public ExpectedException expectedEx = ExpectedException.none(); | ||
@Test | ||
public void testGrow() | ||
{ | ||
int[] a = {3, 5, 7, 8, 9}; | ||
int[] b = {3, 5, 7, 8, 9, 0, 0, 0}; | ||
int[] newArray = myArray.grow(a, 3); | ||
assertArrayEquals(b, newArray); | ||
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// size < 0 抛出异常 | ||
expectedEx.expect(Exception.class); | ||
int[] newArray1 = myArray.grow(a, -3); | ||
assertArrayEquals(b, newArray1); | ||
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} | ||
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@Test | ||
public void testFibonacci() | ||
{ | ||
//max == 1时返回空数组 | ||
int[] array1 = myArray.fibonacci(1); | ||
int[] b = new int[0]; | ||
assertArrayEquals(array1, b); | ||
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int[] array2= myArray.fibonacci(35); | ||
int[] c = {1, 1, 2, 3, 5, 8, 13, 21, 34 }; | ||
assertArrayEquals(c, array2); | ||
} | ||
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@Test | ||
public void testGetPrimes() | ||
{ | ||
int[] a = {2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31 }; | ||
int[] array1 = myArray.getPrimes(35); | ||
assertArrayEquals(a, array1); | ||
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//max <= 2的时候没有素数,数组为空数组 new int[0] | ||
int[] array2 = myArray.getPrimes(1); | ||
int[] b = new int[0]; | ||
assertArrayEquals(array2, b); | ||
} | ||
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@Test | ||
public void testGetPerfectNumbers() | ||
{ | ||
int[] array = myArray.getPerfectNumbers(10000); | ||
int[] a = {6, 28, 496, 8128 }; | ||
assertArrayEquals(a, array); | ||
} | ||
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@Test | ||
public void testJoin() | ||
{ | ||
int[] Array0 = {3, 5, 7, 8, 9}; | ||
String s0 = myArray.join(Array0, "-"); | ||
String s1 = "3-5-7-8-9"; | ||
assertEquals(s1, s0); | ||
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int[] Array1 = {3}; | ||
String s2 = myArray.join(Array1, "-"); | ||
String s3 = "3"; | ||
assertEquals(s2, s3); | ||
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//传递空数组时,返回空数组 | ||
int[] Array2 = new int[0]; | ||
String s4 = myArray.join(Array2, "-"); | ||
String s5 = ""; | ||
assertEquals(s4, s5); | ||
} | ||
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} |
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