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Logic: If there's >1 vCPU: 2 vCPUs - 2 NUMA nodes, each has 1 vCPU 4 vCPUS - 2 NUMA nodes, each has 1 vCPU Otherwise: If num of vCPUs (N) divisible by 4: N/4 NUMA nodes, each has 4 vCPUs If num of vCPUs divisible by 2: N/2 NUMA nodes, each has 2 vCPUs Otherwise, N NUMA nodes, each has 1 vCPU. Tested with 1 - 6 vCPUs.
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Yaniv Kaul
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Feb 26, 2018
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