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工厂方法 #244
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工厂方法 #244
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lxh6688
commented
Jul 15, 2021
- 这个PR解答了当前仓库中的题目(机器人会自动判题并合并当前PR)
- 这个PR修复了当前仓库中的一些代码缺陷(机器人不会判题,而是由管理员来处理当前PR)
🎉 感谢提交Pull Request!请稍等片刻,我们已经将其提交到CI进行检查,一旦有结果会立即通知您! |
@@ -18,7 +18,18 @@ | |||
* @param name 名字 | |||
* @return 创建的猫 | |||
*/ | |||
public static Cat newCat(String name, int age) {} | |||
private Cat(String name,int age){ |
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',' 后应有空格。
'{' 前应有空格。
@@ -18,7 +18,18 @@ | |||
* @param name 名字 | |||
* @return 创建的猫 | |||
*/ | |||
public static Cat newCat(String name, int age) {} | |||
private Cat(String name,int age){ | |||
this.name=name; |
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'=' 后应有空格。
'=' 前应有空格。
public static Cat newCat(String name, int age) {} | ||
private Cat(String name,int age){ | ||
this.name=name; | ||
this.age=age; |
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'=' 后应有空格。
'=' 前应有空格。
} | ||
|
||
public static Cat newCat(String name, int age) { | ||
if(name == null || age< 0.2 || name.isEmpty()){ |
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'if' 后应有空格。
'<' 前应有空格。
'{' 前应有空格。
public static Cat newCat(String name, int age) { | ||
if(name == null || age< 0.2 || name.isEmpty()){ | ||
return INVALID_CAT; | ||
}else{ |
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'}' 后应有空格。
'else' 后应有空格。
'else' 前应有空格。
'{' 前应有空格。
if(name == null || age< 0.2 || name.isEmpty()){ | ||
return INVALID_CAT; | ||
}else{ | ||
return new Cat(name,age); |
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',' 后应有空格。
你的提交 ce346de ,似乎失败了:Your tests failed on CircleCI 😅 请不要气馁,仔细分析原因,再接再厉! |
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你的提交 ce346de ,似乎失败了:Your tests failed on CircleCI 😅 请不要气馁,仔细分析原因,再接再厉! |