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For positive integers $a, s, t$, prove that $a^{\mathrm{gcd}(s,t)}-1=\mathrm{gcd}(a^s-1,a^t-1)$. As a bonus, it can be proven that for any positive integer $n>1$, $n \nmid 2^n-1$.

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bicmr-ai4math/sol-2-16

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For positive integers $a, s, t$, prove that $a^{\mathrm{gcd}(s,t)}-1=\mathrm{gcd}(a^s-1,a^t-1)$. As a bonus, it can be proven that for any positive integer $n>1$, $n \nmid 2^n-1$.

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