misc

resources/posts/2024/2024-05-01-how-adding-type-declarations-makes-your-code-dangerous.md

@@ -27,7 +27,7 @@ It looks like very modern PHP, right? But what if we pass some values:
 $price = new Price('100.82', '2');
 ```
 
-What will be the price's first value? We'd love to see `100.82` float, right?
+What will be the price value? We'd love to see `100.82` float, right?
 
 This is what our code really does ([see 3v4l.org](https://3v4l.org/lKgfG)):
 
@@ -46,7 +46,7 @@ return (int) $value + (string) $anotherValue + (float) $thirdValue;
 Seeing it like this is an obvious red flag, but without using `declare(strict_types=1)`, PHP will silently continue. If we're lucky and we have enabled deprecation warning to trigger errors, we might see:
 
 ```bash
-Deprecated: Implicit conversion from float-string "100.82" to int loses precision in /in/lKgfG on line 5
+Deprecated: Implicit conversion from float-string "100.82" to int loses precision on line 5
 ```
 
 But this is usually lost because we must run our tests with enabled deprecation warnings.