-
Notifications
You must be signed in to change notification settings - Fork 49
Commit
This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository.
Merge pull request #472 from Tech-neophyte/patch-5
day 22-q3 (py3, cpp) solution added #440
- Loading branch information
Showing
1 changed file
with
72 additions
and
0 deletions.
There are no files selected for viewing
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
Original file line number | Diff line number | Diff line change |
---|---|---|
@@ -0,0 +1,72 @@ | ||
## Cpp code: merge sort | ||
``` | ||
/** | ||
* Definition for singly-linked list. | ||
* struct ListNode { | ||
* int val; | ||
* ListNode *next; | ||
* ListNode() : val(0), next(nullptr) {} | ||
* ListNode(int x) : val(x), next(nullptr) {} | ||
* ListNode(int x, ListNode *next) : val(x), next(next) {} | ||
* }; | ||
*/ | ||
class Solution { | ||
public: | ||
/// Merge Function | ||
ListNode *mergeList(ListNode *l1, ListNode *l2){ | ||
ListNode *prev=new ListNode(-1), *curr=prev; | ||
while(l1 and l2){ | ||
if(l1->val<=l2->val){ | ||
curr->next=l1; | ||
l1=l1->next; | ||
}else{ | ||
curr->next=l2; | ||
l2=l2->next; | ||
} | ||
curr=curr->next; | ||
} | ||
if(l1){ | ||
curr->next=l1; | ||
l1=l1->next; | ||
} | ||
if(l2){ | ||
curr->next=l2; | ||
l2=l2->next; | ||
} | ||
return prev->next; | ||
} | ||
/// Divide and Conquer Approach (Merge Sort) | ||
ListNode* sortList(ListNode* head){ | ||
if(!head or !head->next) return head; | ||
ListNode *slow=head, *fast=head, *temp=NULL; | ||
while(fast and fast->next){ | ||
temp=slow; | ||
slow=slow->next; | ||
fast=fast->next->next; | ||
} | ||
temp->next=NULL; | ||
ListNode *point1=sortList(head), *point2=sortList(slow); | ||
return mergeList(point1,point2); | ||
} | ||
}; | ||
``` | ||
## Python code: (Using lists) | ||
``` | ||
class Solution: | ||
def sortList(self, head: Optional[ListNode]) -> Optional[ListNode]: | ||
curr = head | ||
l =[] | ||
while curr: | ||
l.append(curr.val) | ||
curr = curr.next | ||
l.sort() | ||
curr = head | ||
for i in l: | ||
curr.val = i | ||
curr = curr.next | ||
return head | ||
``` |