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🐛 fix feedback when guesses have the same letter multiple times #8

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29 changes: 25 additions & 4 deletions Competition.py
Original file line number Diff line number Diff line change
@@ -1,3 +1,4 @@
from collections import defaultdict, Counter
import inspect
import os
import random
Expand Down Expand Up @@ -50,14 +51,34 @@ def play(self, competitor, word):
print("Competition aborted.")
quit()

guess_result = []
guess_result_dict = defaultdict(lambda: None)
counted = dict(Counter(word))

# first time around we check for well-placed letters
# as it's "free", we also check for letters that are not present
for c in range(5):
if guess[c] not in word:
guess_result.append(LetterInformation.NOT_PRESENT)
guess_result_dict[c] = LetterInformation.NOT_PRESENT
elif word[c] == guess[c]:
guess_result.append(LetterInformation.CORRECT)
guess_result_dict[c] = LetterInformation.CORRECT
# signal this letter has already be used once
counted[guess[c]] -= 1
# second time around, we check for letter that ar present but misplaced
# since we already checked well-placed letter, a letter that is present twice in the
# guess will be accounted correctly
for c in range(5):
if guess_result_dict[c] is not None:
continue
if counted[guess[c]] > 0:
guess_result_dict[c] = LetterInformation.PRESENT
# let's not forget to update how many of that letter rmain in the original word
counted[guess[c]] -= 1
else:
guess_result.append(LetterInformation.PRESENT)
guess_result_dict[c] = LetterInformation.NOT_PRESENT

# transform guess_result back to a list
guess_result = [guess_result_dict[c] for c in range(5)]

guess_history.append((guess, guess_result))
guesses.append(guess)

Expand Down