Add solution and test-cases for problem 2285

leetcode/2201-2300/2285.Maximum-Total-Importance-of-Roads/README.md

@@ -1,28 +1,46 @@
 # [2285.Maximum Total Importance of Roads][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+You are given an integer `n` denoting the number of cities in a country. The cities are numbered from `0` to `n - 1`.
+
+You are also given a 2D integer array `roads` where `roads[i] = [ai, bi]` denotes that there exists a **bidirectional** road connecting cities `ai` and `bi`.
+
+You need to assign each city with an integer value from `1` to `n`, where each value can only be used **once**. The **importance** of a road is then defined as the **sum** of the values of the two cities it connects.
+
+Return the **maximum total importance** of all roads possible after assigning the values optimally.
 
-**Example 1:**
+**Example 1:**  
+
+![1](./ex1drawio.png)
 
 ```
-Input: a = "11", b = "1"
-Output: "100"
+Input: n = 5, roads = [[0,1],[1,2],[2,3],[0,2],[1,3],[2,4]]
+Output: 43
+Explanation: The figure above shows the country and the assigned values of [2,4,5,3,1].
+- The road (0,1) has an importance of 2 + 4 = 6.
+- The road (1,2) has an importance of 4 + 5 = 9.
+- The road (2,3) has an importance of 5 + 3 = 8.
+- The road (0,2) has an importance of 2 + 5 = 7.
+- The road (1,3) has an importance of 4 + 3 = 7.
+- The road (2,4) has an importance of 5 + 1 = 6.
+The total importance of all roads is 6 + 9 + 8 + 7 + 7 + 6 = 43.
+It can be shown that we cannot obtain a greater total importance than 43.
 ```
 
-## 题意
-> ...
+**Example 2:**  
 
-## 题解
+![2](./ex2drawio.png)
 
-### 思路1
-> ...
-Maximum Total Importance of Roads
-```go
 ```
-
+Input: n = 5, roads = [[0,3],[2,4],[1,3]]
+Output: 20
+Explanation: The figure above shows the country and the assigned values of [4,3,2,5,1].
+- The road (0,3) has an importance of 4 + 5 = 9.
+- The road (2,4) has an importance of 2 + 1 = 3.
+- The road (1,3) has an importance of 3 + 5 = 8.
+The total importance of all roads is 9 + 3 + 8 = 20.
+It can be shown that we cannot obtain a greater total importance than 20.
+```
 
 ## 结语
 

leetcode/2201-2300/2285.Maximum-Total-Importance-of-Roads/Solution.go

@@ -1,5 +1,21 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+import "sort"
+
+func Solution(n int, roads [][]int) int64 {
+	ans := int64(0)
+
+	// 检查入读和出度
+	in := make([]int, n)
+	for _, r := range roads {
+		in[r[0]]++
+		in[r[1]]++
+	}
+	sort.Ints(in)
+	v := int64(1)
+	for _, i := range in {
+		ans += v * int64(i)
+		v++
+	}
+	return ans
 }

leetcode/2201-2300/2285.Maximum-Total-Importance-of-Roads/Solution_test.go

@@ -10,30 +10,30 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
-		expect bool
+		n      int
+		roads  [][]int
+		expect int64
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", 5, [][]int{{0, 1}, {1, 2}, {2, 3}, {0, 2}, {1, 3}, {2, 4}}, 43},
+		{"TestCase2", 5, [][]int{{0, 3}, {2, 4}, {1, 3}}, 20},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.n, c.roads)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v",
+					c.expect, got, c.n, c.roads)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }