请实现一个函数按照之字形顺序打印二叉树,即第一行按照从左到右的顺序打印,第二层按照从右到左的顺序打印,第三行再按照从左到右的顺序打印,其他行以此类推。
例如: 给定二叉树: [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
返回其层次遍历结果:
[
[3],
[20,9],
[15,7]
]
提示:
- 节点总数 <= 1000
class Solution:
def levelOrder(self, root: TreeNode) -> List[List[int]]:
if not root:
return []
else:
reverse = False
ans, stack = [], [root]
while stack:
layer_node, layer_val = [], []
while stack:
current = stack.pop(0)
if reverse:
layer_val.insert(0, current.val)
else:
layer_val.append(current.val)
if current.left:
layer_node.append(current.left)
if current.right:
layer_node.append(current.right)
reverse = not reverse
stack.extend(layer_node)
ans.append(layer_val)
return ans