README_EN.md

2520. Count the Digits That Divide a Number

中文文档

Description

Given an integer num, return the number of digits in num that divide num.

An integer val divides nums if nums % val == 0.

 

Example 1:

Input: num = 7
Output: 1
Explanation: 7 divides itself, hence the answer is 1.

Example 2:

Input: num = 121
Output: 2
Explanation: 121 is divisible by 1, but not 2. Since 1 occurs twice as a digit, we return 2.

Example 3:

Input: num = 1248
Output: 4
Explanation: 1248 is divisible by all of its digits, hence the answer is 4.

 

Constraints:

• 1 <= num <= 109
• num does not contain 0 as one of its digits.

Solutions

Python3

class Solution:
    def countDigits(self, num: int) -> int:
        ans, x = 0, num
        while x:
            x, val = divmod(x, 10)
            ans += num % val == 0
        return ans

Java

class Solution {
    public int countDigits(int num) {
        int ans = 0;
        for (int x = num; x > 0; x /= 10) {
            if (num % (x % 10) == 0) {
                ++ans;
            }
        }
        return ans;
    }
}

C++

class Solution {
public:
    int countDigits(int num) {
        int ans = 0;
        for (int x = num; x > 0; x /= 10) {
            if (num % (x % 10) == 0) {
                ++ans;
            }
        }
        return ans;
    }
};

Go

func countDigits(num int) (ans int) {
	for x := num; x > 0; x /= 10 {
		if num%(x%10) == 0 {
			ans++
		}
	}
	return
}

TypeScript

function countDigits(num: number): number {
    let ans = 0;
    let cur = num;
    while (cur !== 0) {
        if (num % (cur % 10) === 0) {
            ans++;
        }
        cur = Math.floor(cur / 10);
    }
    return ans;
}

Rust

impl Solution {
    pub fn count_digits(num: i32) -> i32 {
        let mut ans = 0;
        let mut cur = num;
        while cur != 0 {
            if num % (cur % 10) == 0 {
                ans += 1;
            }
            cur /= 10;
        }
        ans
    }
}

C

int countDigits(int num) {
    int ans = 0;
    int cur = num;
    while (cur) {
        if (num % (cur % 10) == 0) {
            ans++;
        }
        cur /= 10;
    }
    return ans;
}

...