You are given a 0-indexed circular string array words
and a string target
. A circular array means that the array's end connects to the array's beginning.
- Formally, the next element of
words[i]
iswords[(i + 1) % n]
and the previous element ofwords[i]
iswords[(i - 1 + n) % n]
, wheren
is the length ofwords
.
Starting from startIndex
, you can move to either the next word or the previous word with 1
step at a time.
Return the shortest distance needed to reach the string target
. If the string target
does not exist in words
, return -1
.
Example 1:
Input: words = ["hello","i","am","leetcode","hello"], target = "hello", startIndex = 1 Output: 1 Explanation: We start from index 1 and can reach "hello" by - moving 3 units to the right to reach index 4. - moving 2 units to the left to reach index 4. - moving 4 units to the right to reach index 0. - moving 1 unit to the left to reach index 0. The shortest distance to reach "hello" is 1.
Example 2:
Input: words = ["a","b","leetcode"], target = "leetcode", startIndex = 0 Output: 1 Explanation: We start from index 0 and can reach "leetcode" by - moving 2 units to the right to reach index 3. - moving 1 unit to the left to reach index 3. The shortest distance to reach "leetcode" is 1.
Example 3:
Input: words = ["i","eat","leetcode"], target = "ate", startIndex = 0
Output: -1
Explanation: Since "ate" does not exist in words
, we return -1.
Constraints:
1 <= words.length <= 100
1 <= words[i].length <= 100
words[i]
andtarget
consist of only lowercase English letters.0 <= startIndex < words.length
class Solution:
def closetTarget(self, words: List[str], target: str, startIndex: int) -> int:
n = len(words)
ans = n
for i, w in enumerate(words):
if w == target:
t = abs(i - startIndex)
ans = min(ans, t, n - t)
return -1 if ans == n else ans
class Solution {
public int closetTarget(String[] words, String target, int startIndex) {
int n = words.length;
int ans = n;
for (int i = 0; i < n; ++i) {
String w = words[i];
if (w.equals(target)) {
int t = Math.abs(i - startIndex);
ans = Math.min(ans, Math.min(t, n - t));
}
}
return ans == n ? -1 : ans;
}
}
class Solution {
public:
int closetTarget(vector<string>& words, string target, int startIndex) {
int n = words.size();
int ans = n;
for (int i = 0; i < n; ++i) {
auto w = words[i];
if (w == target) {
int t = abs(i - startIndex);
ans = min(ans, min(t, n - t));
}
}
return ans == n ? -1 : ans;
}
};
func closetTarget(words []string, target string, startIndex int) int {
n := len(words)
ans := n
for i, w := range words {
if w == target {
t := abs(i - startIndex)
ans = min(ans, min(t, n-t))
}
}
if ans == n {
return -1
}
return ans
}
func abs(x int) int {
if x < 0 {
return -x
}
return x
}
func min(a, b int) int {
if a < b {
return a
}
return b
}
function closetTarget(
words: string[],
target: string,
startIndex: number,
): number {
const n = words.length;
for (let i = 0; i <= n >> 1; i++) {
if (
words[(startIndex - i + n) % n] === target ||
words[(startIndex + i) % n] === target
) {
return i;
}
}
return -1;
}
impl Solution {
pub fn closet_target(words: Vec<String>, target: String, start_index: i32) -> i32 {
let start_index = start_index as usize;
let n = words.len();
for i in 0..=n >> 1 {
if words[(start_index - i + n) % n] == target || words[(start_index + i) % n] == target
{
return i as i32;
}
}
-1
}
}
int closetTarget(char **words, int wordsSize, char *target, int startIndex) {
for (int i = 0; i <= wordsSize >> 1; i++) {
if (strcmp(words[(startIndex - i + wordsSize) % wordsSize], target) == 0 ||
strcmp(words[(startIndex + i) % wordsSize], target) == 0) {
return i;
}
}
return -1;
}