请你实现一个类 SubrectangleQueries
,它的构造函数的参数是一个 rows x cols
的矩形(这里用整数矩阵表示),并支持以下两种操作:
1. updateSubrectangle(int row1, int col1, int row2, int col2, int newValue)
- 用
newValue
更新以(row1,col1)
为左上角且以(row2,col2)
为右下角的子矩形。
2. getValue(int row, int col)
- 返回矩形中坐标
(row,col)
的当前值。
示例 1:
输入: ["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue","getValue"] [[[[1,2,1],[4,3,4],[3,2,1],[1,1,1]]],[0,2],[0,0,3,2,5],[0,2],[3,1],[3,0,3,2,10],[3,1],[0,2]] 输出: [null,1,null,5,5,null,10,5] 解释: SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,2,1],[4,3,4],[3,2,1],[1,1,1]]); // 初始的 (4x3) 矩形如下: // 1 2 1 // 4 3 4 // 3 2 1 // 1 1 1 subrectangleQueries.getValue(0, 2); // 返回 1 subrectangleQueries.updateSubrectangle(0, 0, 3, 2, 5); // 此次更新后矩形变为: // 5 5 5 // 5 5 5 // 5 5 5 // 5 5 5 subrectangleQueries.getValue(0, 2); // 返回 5 subrectangleQueries.getValue(3, 1); // 返回 5 subrectangleQueries.updateSubrectangle(3, 0, 3, 2, 10); // 此次更新后矩形变为: // 5 5 5 // 5 5 5 // 5 5 5 // 10 10 10 subrectangleQueries.getValue(3, 1); // 返回 10 subrectangleQueries.getValue(0, 2); // 返回 5
示例 2:
输入: ["SubrectangleQueries","getValue","updateSubrectangle","getValue","getValue","updateSubrectangle","getValue"] [[[[1,1,1],[2,2,2],[3,3,3]]],[0,0],[0,0,2,2,100],[0,0],[2,2],[1,1,2,2,20],[2,2]] 输出: [null,1,null,100,100,null,20] 解释: SubrectangleQueries subrectangleQueries = new SubrectangleQueries([[1,1,1],[2,2,2],[3,3,3]]); subrectangleQueries.getValue(0, 0); // 返回 1 subrectangleQueries.updateSubrectangle(0, 0, 2, 2, 100); subrectangleQueries.getValue(0, 0); // 返回 100 subrectangleQueries.getValue(2, 2); // 返回 100 subrectangleQueries.updateSubrectangle(1, 1, 2, 2, 20); subrectangleQueries.getValue(2, 2); // 返回 20
提示:
- 最多有
500
次updateSubrectangle
和getValue
操作。 1 <= rows, cols <= 100
rows == rectangle.length
cols == rectangle[i].length
0 <= row1 <= row2 < rows
0 <= col1 <= col2 < cols
1 <= newValue, rectangle[i][j] <= 10^9
0 <= row < rows
0 <= col < cols
用历史记录列表保存修改历史。
class SubrectangleQueries:
def __init__(self, rectangle: List[List[int]]):
self.g = rectangle
self.ops = []
def updateSubrectangle(
self, row1: int, col1: int, row2: int, col2: int, newValue: int
) -> None:
self.ops.append((row1, col1, row2, col2, newValue))
def getValue(self, row: int, col: int) -> int:
for r1, c1, r2, c2, v in self.ops[::-1]:
if r1 <= row <= r2 and c1 <= col <= c2:
return v
return self.g[row][col]
# Your SubrectangleQueries object will be instantiated and called as such:
# obj = SubrectangleQueries(rectangle)
# obj.updateSubrectangle(row1,col1,row2,col2,newValue)
# param_2 = obj.getValue(row,col)
class SubrectangleQueries {
private int[][] g;
private LinkedList<int[]> ops = new LinkedList<>();
public SubrectangleQueries(int[][] rectangle) {
g = rectangle;
}
public void updateSubrectangle(int row1, int col1, int row2, int col2, int newValue) {
ops.addFirst(new int[] {row1, col1, row2, col2, newValue});
}
public int getValue(int row, int col) {
for (var op : ops) {
if (op[0] <= row && row <= op[2] && op[1] <= col && col <= op[3]) {
return op[4];
}
}
return g[row][col];
}
}
/**
* Your SubrectangleQueries object will be instantiated and called as such:
* SubrectangleQueries obj = new SubrectangleQueries(rectangle);
* obj.updateSubrectangle(row1,col1,row2,col2,newValue);
* int param_2 = obj.getValue(row,col);
*/
class SubrectangleQueries {
public:
vector<vector<int>> g;
vector<vector<int>> ops;
SubrectangleQueries(vector<vector<int>>& rectangle) {
g = rectangle;
}
void updateSubrectangle(int row1, int col1, int row2, int col2, int newValue) {
ops.push_back({row1, col1, row2, col2, newValue});
}
int getValue(int row, int col) {
for (int i = ops.size() - 1; ~i; --i) {
auto op = ops[i];
if (op[0] <= row && row <= op[2] && op[1] <= col && col <= op[3]) {
return op[4];
}
}
return g[row][col];
}
};
/**
* Your SubrectangleQueries object will be instantiated and called as such:
* SubrectangleQueries* obj = new SubrectangleQueries(rectangle);
* obj->updateSubrectangle(row1,col1,row2,col2,newValue);
* int param_2 = obj->getValue(row,col);
*/
type SubrectangleQueries struct {
g [][]int
ops [][]int
}
func Constructor(rectangle [][]int) SubrectangleQueries {
return SubrectangleQueries{rectangle, [][]int{}}
}
func (this *SubrectangleQueries) UpdateSubrectangle(row1 int, col1 int, row2 int, col2 int, newValue int) {
this.ops = append(this.ops, []int{row1, col1, row2, col2, newValue})
}
func (this *SubrectangleQueries) GetValue(row int, col int) int {
for i := len(this.ops) - 1; i >= 0; i-- {
op := this.ops[i]
if op[0] <= row && row <= op[2] && op[1] <= col && col <= op[3] {
return op[4]
}
}
return this.g[row][col]
}
/**
* Your SubrectangleQueries object will be instantiated and called as such:
* obj := Constructor(rectangle);
* obj.UpdateSubrectangle(row1,col1,row2,col2,newValue);
* param_2 := obj.GetValue(row,col);
*/
class SubrectangleQueries {
g: number[][];
ops: number[][];
constructor(rectangle: number[][]) {
this.g = rectangle;
this.ops = [];
}
updateSubrectangle(
row1: number,
col1: number,
row2: number,
col2: number,
newValue: number,
): void {
this.ops.push([row1, col1, row2, col2, newValue]);
}
getValue(row: number, col: number): number {
for (let i = this.ops.length - 1; ~i; --i) {
const [r1, c1, r2, c2, v] = this.ops[i];
if (r1 <= row && row <= r2 && c1 <= col && col <= c2) {
return v;
}
}
return this.g[row][col];
}
}
/**
* Your SubrectangleQueries object will be instantiated and called as such:
* var obj = new SubrectangleQueries(rectangle)
* obj.updateSubrectangle(row1,col1,row2,col2,newValue)
* var param_2 = obj.getValue(row,col)
*/