README_EN.md

1122. Relative Sort Array

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Description

Given two arrays arr1 and arr2, the elements of arr2 are distinct, and all elements in arr2 are also in arr1.

Sort the elements of arr1 such that the relative ordering of items in arr1 are the same as in arr2. Elements that do not appear in arr2 should be placed at the end of arr1 in ascending order.

 

Example 1:

Input: arr1 = [2,3,1,3,2,4,6,7,9,2,19], arr2 = [2,1,4,3,9,6]
Output: [2,2,2,1,4,3,3,9,6,7,19]

Example 2:

Input: arr1 = [28,6,22,8,44,17], arr2 = [22,28,8,6]
Output: [22,28,8,6,17,44]

 

Constraints:

• 1 <= arr1.length, arr2.length <= 1000
• 0 <= arr1[i], arr2[i] <= 1000
• All the elements of arr2 are distinct.
• Each arr2[i] is in arr1.

Solutions

Python3

class Solution:
    def relativeSortArray(self, arr1: List[int], arr2: List[int]) -> List[int]:
        mp = {num: i for i, num in enumerate(arr2)}
        arr1.sort(key=lambda x: (mp.get(x, 10000), x))
        return arr1

class Solution:
    def relativeSortArray(self, arr1: List[int], arr2: List[int]) -> List[int]:
        mp = [0] * 1001
        for x in arr1:
            mp[x] += 1
        i = 0
        for x in arr2:
            while mp[x] > 0:
                arr1[i] = x
                mp[x] -= 1
                i += 1
        for x, cnt in enumerate(mp):
            for _ in range(cnt):
                arr1[i] = x
                i += 1
        return arr1

Java

class Solution {
    public int[] relativeSortArray(int[] arr1, int[] arr2) {
        int[] mp = new int[1001];
        for (int x : arr1) {
            ++mp[x];
        }
        int i = 0;
        for (int x : arr2) {
            while (mp[x]-- > 0) {
                arr1[i++] = x;
            }
        }
        for (int j = 0; j < mp.length; ++j) {
            while (mp[j]-- > 0) {
                arr1[i++] = j;
            }
        }
        return arr1;
    }
}

C++

class Solution {
public:
    vector<int> relativeSortArray(vector<int>& arr1, vector<int>& arr2) {
        vector<int> mp(1001);
        for (int x : arr1) ++mp[x];
        int i = 0;
        for (int x : arr2) {
            while (mp[x]-- > 0) arr1[i++] = x;
        }
        for (int j = 0; j < mp.size(); ++j) {
            while (mp[j]-- > 0) arr1[i++] = j;
        }
        return arr1;
    }
};

Go

func relativeSortArray(arr1 []int, arr2 []int) []int {
	mp := make([]int, 1001)
	for _, x := range arr1 {
		mp[x]++
	}
	i := 0
	for _, x := range arr2 {
		for mp[x] > 0 {
			arr1[i] = x
			mp[x]--
			i++
		}
	}
	for j, cnt := range mp {
		for cnt > 0 {
			arr1[i] = j
			i++
			cnt--
		}
	}
	return arr1
}

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