Given strings s1
and s2
, return the minimum contiguous substring part of s1
, so that s2
is a subsequence of the part.
If there is no such window in s1
that covers all characters in s2
, return the empty string ""
. If there are multiple such minimum-length windows, return the one with the left-most starting index.
Example 1:
Input: s1 = "abcdebdde", s2 = "bde" Output: "bcde" Explanation: "bcde" is the answer because it occurs before "bdde" which has the same length. "deb" is not a smaller window because the elements of s2 in the window must occur in order.
Example 2:
Input: s1 = "jmeqksfrsdcmsiwvaovztaqenprpvnbstl", s2 = "u" Output: ""
Constraints:
1 <= s1.length <= 2 * 104
1 <= s2.length <= 100
s1
ands2
consist of lowercase English letters.