Given an integer array nums
of unique elements, return all possible subsets (the power set).
The solution set must not contain duplicate subsets. Return the solution in any order.
Example 1:
Input: nums = [1,2,3] Output: [[],[1],[2],[1,2],[3],[1,3],[2,3],[1,2,3]]
Example 2:
Input: nums = [0] Output: [[],[0]]
Constraints:
1 <= nums.length <= 10
-10 <= nums[i] <= 10
- All the numbers of
nums
are unique.
DFS.
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
def dfs(u, t):
if u == len(nums):
ans.append(t[:])
return
dfs(u + 1, t)
t.append(nums[u])
dfs(u + 1, t)
t.pop()
ans = []
dfs(0, [])
return ans
class Solution:
def subsets(self, nums: List[int]) -> List[List[int]]:
ans = []
for mask in range(1 << len(nums)):
t = []
for i, v in enumerate(nums):
if (mask >> i) & 1:
t.append(v)
ans.append(t)
return ans
class Solution {
private List<List<Integer>> ans = new ArrayList<>();
private int[] nums;
public List<List<Integer>> subsets(int[] nums) {
this.nums = nums;
dfs(0, new ArrayList<>());
return ans;
}
private void dfs(int u, List<Integer> t) {
if (u == nums.length) {
ans.add(new ArrayList<>(t));
return;
}
dfs(u + 1, t);
t.add(nums[u]);
dfs(u + 1, t);
t.remove(t.size() - 1);
}
}
class Solution {
public List<List<Integer>> subsets(int[] nums) {
int n = nums.length;
List<List<Integer>> ans = new ArrayList<>();
for (int mask = 0; mask < 1 << n; ++mask) {
List<Integer> t = new ArrayList<>();
for (int i = 0; i < n; ++i) {
if (((mask >> i) & 1) == 1) {
t.add(nums[i]);
}
}
ans.add(t);
}
return ans;
}
}
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> ans;
vector<int> t;
dfs(0, nums, t, ans);
return ans;
}
void dfs(int u, vector<int>& nums, vector<int>& t, vector<vector<int>>& ans) {
if (u == nums.size()) {
ans.push_back(t);
return;
}
dfs(u + 1, nums, t, ans);
t.push_back(nums[u]);
dfs(u + 1, nums, t, ans);
t.pop_back();
}
};
class Solution {
public:
vector<vector<int>> subsets(vector<int>& nums) {
vector<vector<int>> ans;
vector<int> t;
int n = nums.size();
for (int mask = 0; mask < 1 << n; ++mask)
{
t.clear();
for (int i = 0; i < n; ++i)
{
if ((mask >> i) & 1)
{
t.push_back(nums[i]);
}
}
ans.push_back(t);
}
return ans;
}
};
func subsets(nums []int) [][]int {
var ans [][]int
var dfs func(u int, t []int)
dfs = func(u int, t []int) {
if u == len(nums) {
ans = append(ans, append([]int(nil), t...))
return
}
dfs(u+1, t)
t = append(t, nums[u])
dfs(u+1, t)
t = t[:len(t)-1]
}
var t []int
dfs(0, t)
return ans
}
func subsets(nums []int) [][]int {
var ans [][]int
n := len(nums)
for mask := 0; mask < 1<<n; mask++ {
t := []int{}
for i, v := range nums {
if ((mask >> i) & 1) == 1 {
t = append(t, v)
}
}
ans = append(ans, t)
}
return ans
}
function subsets(nums: number[]): number[][] {
const n = nums.length;
const t: number[] = [];
const res: number[][] = [];
const dfs = (i: number) => {
if (i === n) {
res.push([...t]);
return;
}
dfs(i + 1);
t.push(nums[i]);
dfs(i + 1);
t.pop();
};
dfs(0);
return res;
}
impl Solution {
fn dfs(i: usize, path: &mut Vec<i32>, res: &mut Vec<Vec<i32>>, nums: &Vec<i32>) {
if i == nums.len() {
res.push(path.clone());
return;
}
Self::dfs(i + 1, path, res, nums);
path.push(nums[i]);
Self::dfs(i + 1, path, res, nums);
path.pop();
}
pub fn subsets(nums: Vec<i32>) -> Vec<Vec<i32>> {
let mut res = Vec::new();
Self::dfs(0, &mut Vec::new(), &mut res, &nums);
res
}
}