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When using urllib.parse to get username and password, sometimes the password would contain unsafe characters like /, if it has / in password, urlparse will fail to parse username and password. For example, if url = 'kerberos+pw://domain\\user:Secret/[email protected]', the urlparse(url).username and urlparse(url).password will be empty.
Is this possible to be solved?
The text was updated successfully, but these errors were encountered:
Hello,
minikerberos/minikerberos/common/factory.py
Lines 175 to 180 in d2cd8ea
When using urllib.parse to get username and password, sometimes the password would contain unsafe characters like
/
, if it has/
in password,urlparse
will fail to parse username and password. For example, ifurl = 'kerberos+pw://domain\\user:Secret/[email protected]'
, theurlparse(url).username
andurlparse(url).password
will be empty.Is this possible to be solved?
The text was updated successfully, but these errors were encountered: