variable problem input.http #3063
lowepalma
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Hi! Do you have any of of the error when using the variable? |
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Can someone help me, I have this function if I write the url it works fine if I use a variable it doesn't work and if I check the value of the variable by log it is the same as the one I write:
def get_radio_source(url) =
if !stream_connected then
# Si no hay conexión activa, utilizar la lista de reproducción
playlist
else
# Si hay conexión activa, utilizar el stream
input.http(stream_url)
#input.http("https://eu1.xxxxxxx.es:2959/stream")
end
end
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