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I've converted this into a Discussion because it doesn't pertain to a bug or feature request. Yes, the heat of formation includes a solvation energy that is meant to approximate the molecule-solvent interaction and how the molecule changes the energy of the solvent itself (modeled crudely as charge rearrangements in a dielectric continuum). I would need to review the COSMO model more carefully to provide a more precise answer, but the dielectric energy contains the direct contributions to the heat of formation from solvent effects. In your simple example where symmetry prevents the solvent from causing any charge rearrangements, it is exactly the difference between the heat of formation of the molecule in and out of the implicit solvent. In general, the solvent model will cause charge rearrangements in the molecule, and so the difference between heats in and out of solvent will not match the dielectric energy exactly (although it is usually close). |
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I'm wondering if the value reported in "FINAL HEAT OF FORMATION" includes the contribution from "DIELECTRIC ENERGY".
The following experiment with an ion in implicit solvent vs vacuum suggests it does, but I'd like to confirm since it doesn't seem the documentation states that either way. Thanks!
Input1:
Output1:
Input 2:
Output 2:
Dielectric energy = -3.48258 EV == -336.018 kJ/mol
Difference in heats of formation = -588.03762 - (-252.01975) kJ/mol == -336.01787 kJ/mol, this matches exactly, suggesting the dielectric energy is included
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