AJAX原生代码.html

<script type="text/javascript">
var url = "https://www.easy-mock.com/mock/5bad8210a1b7f6239a61664f/pcTest";
var xhr = new XMLHttpRequest()
xhr.open('get', url)
xhr.send();//发送请求
xhr.onreadystatechange = function() {
  if (xhr.readyState === 4 && xhr.status == 200) {
    var reponse = xhr.responseText;
    //JSON.parse()将字符串转为json对象
    var name = JSON.parse(reponse).data.name;
    console.log(name)
  }
}

</script>