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Populating Next Right Pointers in Each Node
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Populating Next Right Pointers in Each Node
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/*
// Definition for a Node.
class Node {
public:
int val;
Node* left;
Node* right;
Node* next;
Node() : val(0), left(NULL), right(NULL), next(NULL) {}
Node(int _val) : val(_val), left(NULL), right(NULL), next(NULL) {}
Node(int _val, Node* _left, Node* _right, Node* _next)
: val(_val), left(_left), right(_right), next(_next) {}
};
*/
class Solution {
public:
Node* connect(Node* root) {
//Kind of morris traversal - Itretive approach
// if(root == NULL) return NULL;
// Node* pre=root;
// Node* curr=NULL;
// while(pre->left){
// curr=pre;
// while(curr){
// //connects the left subtree of same level
// //with right subtree of that same level
// curr->left->next = curr->right;
// //connect the rightmost node of a level
// //to the leftmost node of the next level.
// if (curr -> next) curr->right->next = curr->next->left;
// curr = curr->next;
// }
// pre=pre->left;
// }
// return root;
//Recursive Approach
// if(root == NULL) return NULL;
// //connects the left subtree of same level
// //with right subtree of that same level
// if(root->left) root->left->next = root->right;
// //connect the rightmost node of a level to
// //the leftmost node of the next level.
// if(root->right && root->next) root->right->next = root->next->left;
// //recursive calls for left and right subtrees.
// connect(root->left);
// connect(root->right);
// return root;
// }
//Using queue
if (!root)
return NULL;
queue<Node*> q;
q.push(root);
while (!q.empty())
{
int size = q.size();
while (size--)
{
Node* node = q.front();
q.pop();
if (size > 0)
node->next = q.front();
if (node->left)
q.push(node->left);
if (node->right)
q.push(node->right);
}
}
return root;
}
};