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1619.删除某些元素后的数组均值.go
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1619.删除某些元素后的数组均值.go
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/*
* @lc app=leetcode.cn id=1619 lang=golang
*
* [1619] 删除某些元素后的数组均值
*
* https://leetcode-cn.com/problems/mean-of-array-after-removing-some-elements/description/
*
* algorithms
* Easy (66.88%)
* Likes: 21
* Dislikes: 0
* Total Accepted: 9.4K
* Total Submissions: 14K
* Testcase Example: '[1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,3]'
*
* 给你一个整数数组 arr ,请你删除最小 5% 的数字和最大 5% 的数字后,剩余数字的平均值。
*
* 与 标准答案 误差在 10^-5 的结果都被视为正确结果。
*
*
*
* 示例 1:
*
*
* 输入:arr = [1,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,2,3]
* 输出:2.00000
* 解释:删除数组中最大和最小的元素后,所有元素都等于 2,所以平均值为 2 。
*
*
* 示例 2:
*
*
* 输入:arr = [6,2,7,5,1,2,0,3,10,2,5,0,5,5,0,8,7,6,8,0]
* 输出:4.00000
*
*
* 示例 3:
*
*
* 输入:arr =
* [6,0,7,0,7,5,7,8,3,4,0,7,8,1,6,8,1,1,2,4,8,1,9,5,4,3,8,5,10,8,6,6,1,0,6,10,8,2,3,4]
* 输出:4.77778
*
*
* 示例 4:
*
*
* 输入:arr =
* [9,7,8,7,7,8,4,4,6,8,8,7,6,8,8,9,2,6,0,0,1,10,8,6,3,3,5,1,10,9,0,7,10,0,10,4,1,10,6,9,3,6,0,0,2,7,0,6,7,2,9,7,7,3,0,1,6,1,10,3]
* 输出:5.27778
*
*
* 示例 5:
*
*
* 输入:arr =
* [4,8,4,10,0,7,1,3,7,8,8,3,4,1,6,2,1,1,8,0,9,8,0,3,9,10,3,10,1,10,7,3,2,1,4,9,10,7,6,4,0,8,5,1,2,1,6,2,5,0,7,10,9,10,3,7,10,5,8,5,7,6,7,6,10,9,5,10,5,5,7,2,10,7,7,8,2,0,1,1]
* 输出:5.29167
*
*
*
*
* 提示:
*
*
* 20
* arr.length 是 20 的 倍数
* 0
*
*
*/
// @lc code=start
func trimMean(arr []int) float64 {
sort.Ints(arr)
size := len(arr)
del := int(float64(size) * 0.05)
sum := 0
for i := del; i < size-del; i++ {
sum += arr[i]
}
return float64(sum) / float64(size-del*2)
}
// @lc code=end