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_15_ThreeSum.java
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_15_ThreeSum.java
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package leetcode_1To300;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _15_ThreeSum {
/**
*
For example, given array S = [-1, 0, 1, 2, -1, -4],
A solution set is:
[
[-1, 0, 1],
[-1, -1, 2]
]
[-4, -1, -1, 0, 1, 2]
time : O(n^2);
space : O(n^2);
* @param nums
* @return
*/
public List<List<Integer>> threeSum(int[] nums) {
List<List<Integer>> res = new ArrayList<>();
Arrays.sort(nums);
for (int i = 0; i < nums.length - 2; i++) {
if (i > 0 && nums[i] == nums[i - 1]) continue;
int low = i + 1, high = nums.length - 1;
int sum = 0 - nums[i];
while (low < high) {
if (nums[low] + nums[high] == sum) {
res.add(Arrays.asList(nums[i], nums[low], nums[high]));
while (low < high && nums[low] == nums[low + 1]) low++;
while (low < high && nums[high] == nums[high - 1]) high--;
low++;
high--;
} else if (nums[low] + nums[high] < sum) {
low++;
} else {
high--;
}
}
}
return res;
}
}