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_159_LongestSubstringwithAtMostTwoDistinctCharacters.java
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_159_LongestSubstringwithAtMostTwoDistinctCharacters.java
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package leetcode_1To300;
import java.util.HashMap;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _159_LongestSubstringwithAtMostTwoDistinctCharacters {
/**
* 159. Longest Substring with At Most Two Distinct Characters
* Given a string, find the length of the longest substring T that contains at most 2 distinct characters.
For example, Given s = “eceba”,
T is "ece" which its length is 3.
sliding window
“eceba”
time : O(n)
space : O(n)
* @param s
* @return
*/
public int lengthOfLongestSubstringTwoDistinct(String s) {
if (s == null || s.length() == 0) return 0;
HashMap<Character, Integer> map = new HashMap<>();
int start = 0, end = 0;
int res = 0;
while (end < s.length()) {
if (map.size() <= 2) {
map.put(s.charAt(end), end);
end++;
}
if (map.size() > 2) {
int leftMost = s.length();
for (int num : map.values()) {
leftMost = Math.min(leftMost, num);
}
map.remove(s.charAt(leftMost));
start = leftMost + 1;
}
res = Math.max(res, end - start);
}
return res;
}
}