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_152_MaximumProductSubarray.java
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_152_MaximumProductSubarray.java
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package leetcode_1To300;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _152_MaximumProductSubarray {
/**
* 152. Maximum Product Subarray
* For example, given the array [2,3,-2,4],
the contiguous subarray [2,3] has the largest product = 6.
time : O(n)
space : O(1)
* @param nums
* @return
*/
public int maxProduct(int[] nums) {
if (nums == null || nums.length == 0) return 0;
int max = nums[0];
int min = nums[0];
int res = nums[0];
for (int i = 1; i < nums.length; i++) {
int temp = max;
max = Math.max(Math.max(max * nums[i], min * nums[i]), nums[i]);
min = Math.min(Math.min(min * nums[i], temp * nums[i]), nums[i]);
res = Math.max(res, max);
}
return res;
}
}