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_150_EvaluateReversePolishNotation.java
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_150_EvaluateReversePolishNotation.java
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package leetcode_1To300;
import java.util.Stack;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _150_EvaluateReversePolishNotation {
/**
* 150. Evaluate Reverse Polish Notation
* Valid operators are +, -, *, /. Each operand may be an integer or another expression.
Some examples:
["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9
["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6
time : O(n)
space : O(n)
* @param tokens
* @return
*/
public int evalRPN(String[] tokens) {
Stack<Integer> stack = new Stack<>();
for (String s : tokens) {
if (s.equals("+")) {
stack.push(stack.pop() + stack.pop());
} else if (s.equals("-")) {
int b = stack.pop();
int a = stack.pop();
stack.push(a - b);
} else if (s.equals("*")) {
stack.push(stack.pop() * stack.pop());
} else if (s.equals("/")) {
int b = stack.pop();
int a = stack.pop();
stack.push(a / b);
} else {
stack.push(Integer.parseInt(s));
}
}
return stack.pop();
}
}