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_137_SingleNumberII.java
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package leetcode_1To300;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _137_SingleNumberII {
/**
* 137. Single Number II
* Given an array of integers, every element appears three times except for one, which appears exactly once.
* Find that single one
0 -> 1 -> 2 -> 0
00 -> 01 -> 10 -> 00
00 -> 10 -> 01 -> 00
ones twos
0 0
0 -> 1 0 -> 0
1 -> 0 0 -> 1
0 -> 0 1 -> 0
1, 存入ones里
2,清空ones 存入twos
3,twos进行清空
time : O(n)
space : O(1)
* @param nums
* @return
*/
public int singleNumber(int[] nums) {
int ones = 0, twos = 0;
for (int i = 0; i < nums.length; i++) {
ones = (ones ^ nums[i]) & ~twos;
twos = (twos ^ nums[i]) & ~ones;
}
return ones;
}
}