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_114_FlattenBinaryTreetoLinkedList.java
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_114_FlattenBinaryTreetoLinkedList.java
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package leetcode_1To300;
import java.util.Stack;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _114_FlattenBinaryTreetoLinkedList {
/**
* 114. Flatten Binary Tree to Linked List
* For example,
Given
1
/ \
2 5
/ \ \
3 4 6
The flattened tree should look like:
1
\
2
\
3
\
4
\
5
\
6
time : O(n)
space : O(n)
* @param root
*/
private TreeNode prev = null;
public void flatten(TreeNode root) {
if (root == null) return;
flatten(root.right);
flatten(root.left);
root.right = prev;
root.left = null;
prev = root;
}
public void flatten2(TreeNode root) {
if (root == null) return;
Stack<TreeNode> stack = new Stack<>();
stack.push(root);
while (!stack.isEmpty()) {
TreeNode cur = stack.pop();
if (cur.right != null) stack.push(cur.right);
if (cur.left != null) stack.push(cur.left);
if (!stack.isEmpty()) {
cur.right = stack.peek();
}
cur.left = null;
}
}
}