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26.go
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26.go
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package easy_collection
/**
* 26. Remove Duplicates from Sorted Array
* <p>
* Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length.
* <p>
* Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.
* <p>
* Example 1:
* <p>
* Given nums = [1,1,2],
* <p>
* Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively.
* <p>
* It doesn't matter what you leave beyond the returned length.
* <p>
* Example 2:
* <p>
* Given nums = [0,0,1,1,1,2,2,3,3,4],
* <p>
* Your function should return length = 5, with the first five elements of nums being modified to 0, 1, 2, 3, and 4 respectively.
* <p>
* It doesn't matter what values are set beyond the returned length.
* <p>
* Clarification:
* <p>
* Confused why the returned value is an integer but your answer is an array?
* <p>
* Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well.
* <p>
* Internally you can think of this:
* <p>
* // nums is passed in by reference. (i.e., without making a copy)
* int len = removeDuplicates(nums);
* <p>
* // any modification to nums in your function would be known by the caller.
* // using the length returned by your function, it prints the first len elements.
* for (int i = 0; i < len; i++) {
* print(nums[i]);
* }
*/
func removeDuplicates(nums []int) int {
index := 0
for _, n := range nums {
if nums[index] != n {
index++
nums[index] = n
}
}
index++
return index
}