component.set_input_types() and component.set_input_type() let's user set non-existing inputs

[silvanocerza]

Describe the bug

If a user calls component.set_input_types() or component.set_input_type() in a Component's init method the inputs will be added even if the Component doesn't define a run method that accepts **kwargs.

Expected behavior

Setting an input in a Component init that has a run that doesn't accept **kwargs must fail.

To Reproduce

This sould fail:

@component
class Foo:
    def __init__(self):
        component.set_input_types(self, y=int)

    @component.output_types(output=int)
    def run(self, x: int):
        return {"output": x}


print(Foo())
# <__main__.Foo object at 0x106190500>
# Inputs:
#   - y: int
#   - x: int
# Outputs:
#   - output: int

This should fail too:

@component
class Bar:
    def __init__(self):
        component.set_input_type(self, "y", int)

    @component.output_types(output=int)
    def run(self, x: int):
        return {"output": x}

print(Bar())
# <__main__.Bar object at 0x13998ea80>
# Inputs:
#   - y: int
#   - x: int
# Outputs:
#   - output: int

This is correct instead:

@component
class Baz:
    def __init__(self):
        component.set_input_type(self, "y", int)

    @component.output_types(output=int)
    def run(self, x: int, **kwargs):
        return {"output": x + kwargs.get("y")}

print(Baz())
# <__main__.Baz object at 0x13998ec30>
# Inputs:
#   - y: int
#   - x: int
# Outputs:
#   - output: int

[shadeMe]

We should also raise an error if set_input_types overrides the type of an existing non-kwarg parameter of the run method.