_2678. Number of Senior Citizens.md

2678. Number of Senior Citizens

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First completed : May 22, 2024

Last updated : August 01, 2024

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Related Topics : Array, String

Acceptance Rate : 81.45 %

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Solutions

• e2678 v1.c
• e2678 v1.py
• e2678 v2 oneliner.py
• e2678 v3 oneliner.py
• e2678.java

C

e2678 v1.c

int countSeniors(char ** details, int detailsSize){
    int output = 0;
    for (int i = 0; i < detailsSize; i++) {
        if ((details[i][11] - '0') * 10 + details[i][12] - '0' > 60) {
            output++;
        }
    }
    return output;
}

Python

e2678 v1.py

class Solution:
    def countSeniors(self, details: List[str]) -> int:
        counter = 0
        for detail in details :
            if int(detail[11:13]) > 60 :
                counter += 1
        return counter

e2678 v2 oneliner.py

class Solution:
    def countSeniors(self, details: List[str]) -> int:
        return sum([int(x[11:13]) > 60 for x in details])

e2678 v3 oneliner.py

class Solution:
    def countSeniors(self, details: List[str]) -> int:
        return [True for x in details if int(x[11:13]) > 60].count(True)

Java

e2678.java

class Solution {
    public int countSeniors(String[] details) {
        int counter = 0;
        for (String str : details) {
            if (Integer.parseInt(str.substring(11,13)) > 60) {
                counter++;
            }
        }
        return counter;
    }
}