Sum of 10 bytes of data

Write an Assembly Language program to sum 10 bytes of data, the sum may exceed 8 bits, store the lower byte of the sum at memory location 3000H and upper byte at 3010H.
INPUT: E4, A0, FF, CD, A4, 16, F1, B2, 56, 67
OUTPUT: (3000H): 06
(3010H):6A

Approach : simply add number by number if number exceeds 8 bit then keep track on how many time exceed in different bit .
use JC insrtuction if carry generated ( carry flag = set ) => increment exceeds bit
answer => total exceeds bit + content of accumlator

Code : 

MVI A,00H
LXI B,3000H
LXI H,3020H
MVI E,10
MVI D,00H ; exceeded bit
LOOP:ADD M
	   INR L
     DCR E
	   JC INCR ; check sum exceeds 8 bit or not 
     JZ END
	   JMP LOOP

INCR:INR D
	   JMP LOOP

END:MOV E,A
	  MOV A,D
	  STAX B
	  LXI B,3010H
    MOV A,E
    STAX B
    HLT