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A_Subsequence_Permutation.cpp
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A_Subsequence_Permutation.cpp
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#include<bits/stdc++.h>
#define pb push_back
#define mp make_pair
#define fr first
#define sc second
#define clr(a) memset(a, 0, sizeof(a))
#define sz(x) x.size()
#define rep(n) for (ll i = 0; i < n; i++)
#define repc(i, n) for (ll i = 0; i < n; i++)
#define FOR(i, x, y) for (int i = x; i < y; i++)
#define DEC(i, x, y) for (int i = x; i >= y; i--)
#define all(v) v.begin(), v.end()
#define min3(a, b, c) min(a, min(b, c))
#define max3(a, b, c) max(a, max(b, c))
#define alla(a, n) a, a + n
using namespace std;
// Some typedef's
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll> ii;
typedef vector<ll> vi;
typedef vector<ii> vii;
// Some frequently used functions
template <typename T>
T modpow(T base, T exp, T modulus){
base %= modulus; T result = 1;
while(exp > 0){
if(exp & 1) result = (result * base) % modulus;
base = (base * base) % modulus;
exp >>= 1;
}
return result;
}
ll lcm(ll a, ll b) { return (a * (b / __gcd(a, b))); }
//Repeat the problem statement,Example(Random testcases),Approach,Code,Testcases,Optimize,Upsolving,30-45minutes
// 6 probs a day! atleast
// participate in every contest
// int overflow, array bounds special cases (n=1?)
// if u wont someone else will..
// do smth instead of nothing and stay organized
// WRITE STUFF DOWN DON'T GET STUCK ON ONE APPROACH
// Some contants
const int inf = 1e9 + 7;
const double eps = 1e-6;
const double pi = 1.00 * acos(-1.00);
void solve(){
int n;
cin >> n;
string s;
cin >> s;
string s1 = s;
sort(s.begin(),s.end());
int cnt = 0;
for(int i = 0; i < n; i++){
if(s[i] == s1[i]){
continue;
}
else{
cnt++;
}
}
cout << cnt << endl;
}
int main(){
ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL) ;
int t;
cin >> t;
while(t--){
solve();
}
}