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_386_LexicographicalNumbers.java
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_386_LexicographicalNumbers.java
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package leetcode_1To300;
import java.util.ArrayList;
import java.util.List;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _386_LexicographicalNumbers {
/**
* 386. Lexicographical Numbers
* Given an integer n, return 1 - n in lexicographical order.
For example, given 13, return: [1,10,11,12,13,2,3,4,5,6,7,8,9].
Please optimize your algorithm to use less time and space. The input size may be as large as 5,000,000.
time : O(n);
space : O(n);
* @param n
* @return
*/
public List<Integer> lexicalOrder(int n) {
List<Integer> res = new ArrayList<>();
int cur = 1;
for (int i = 1; i <= n; i++) {
res.add(cur);
if (cur * 10 <= n) {
cur *= 10;
} else if (cur % 10 != 9 && cur + 1 <= n) {
cur++;
} else {
while ((cur / 10) % 10 == 9) {
cur /= 10;
}
cur = cur / 10 + 1;
}
}
return res;
}
}