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_343_IntegerBreak.java
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_343_IntegerBreak.java
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package leetcode_1To300;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _343_IntegerBreak {
/**
* 343. Integer Break
* Given a positive integer n, break it into the sum of at least two positive integers and
* maximize the product of those integers. Return the maximum product you can get.
For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 + 3 + 4).
2 : 1 + 1
3 : 2 + 1
4 : 2 + 2
5 : 3 + 2
6 : 3 + 3
7 : 3 + 4
8 : 3 + 3 + 2
9 : 3 + 3 + 3
10 : 3 + 3 + 4
time : < O(n) O(1)
space : O(1)
* @param n
* @return
*/
public int integerBreak(int n) {
if (n == 2 || n == 3) return n - 1;
int res = 1;
while (n > 4) {
res *= 3;
n -= 3;
}
return res * n;
}
}