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_311_SparseMatrixMultiplication.java
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_311_SparseMatrixMultiplication.java
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package leetcode_1To300;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _311_SparseMatrixMultiplication {
/**
* 311. Sparse Matrix Multiplication
* Example:
A = [
[ 1, 0, 0],
[-1, 0, 3]
]
B = [
[ 7, 0, 0 ],
[ 0, 0, 0 ],
[ 0, 0, 1 ]
]
| 1 0 0 | | 7 0 0 | | 7 0 0 |
AB = | -1 0 3 | x | 0 0 0 | = | -7 0 3 |
| 0 0 1 |
time : O(m * n *nB)
space : O(m * nB)
* @param A
* @param B
* @return
*/
public int[][] multiply(int[][] A, int[][] B) {
int m = A.length, n = A[0].length;
int nB = B[0].length;
int[][] res = new int[m][nB];
for (int i = 0; i < m; i++) {
for (int k = 0; k < n; k++) {
if (A[i][k] != 0) {
for (int j = 0; j < nB; j++) {
if (B[k][j] != 0) res[i][j] += A[i][k] * B[k][j];
}
}
}
}
return res;
}
}