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_306_AdditiveNumber.java
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_306_AdditiveNumber.java
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package leetcode_1To300;
/**
* 本代码来自 Cspiration,由 @Cspiration 提供
* 题目来源:http://leetcode.com
* - Cspiration 致力于在 CS 领域内帮助中国人找到工作,让更多海外国人受益
* - 现有课程:Leetcode Java 版本视频讲解(1-900题)(上)(中)(下)三部
* - 算法基础知识(上)(下)两部;题型技巧讲解(上)(下)两部
* - 节省刷题时间,效率提高2-3倍,初学者轻松一天10题,入门者轻松一天20题
* - 讲师:Edward Shi
* - 官方网站:https://cspiration.com
* - 版权所有,转发请注明出处
*/
public class _306_AdditiveNumber {
/**
* 306. Additive Number
* Additive number is a string whose digits can form additive sequence.
A valid additive sequence should contain at least three numbers. Except for the first two numbers,
each subsequent number in the sequence must be the sum of the preceding two.
For example:
"112358" is an additive number because the digits can form an additive sequence: 1, 1, 2, 3, 5, 8.
1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, 3 + 5 = 8
"199100199" is also an additive number, the additive sequence is: 1, 99, 100, 199.
1 + 99 = 100, 99 + 100 = 199
Note: Numbers in the additive sequence cannot have leading zeros,
so sequence 1, 2, 03 or 1, 02, 3 is invalid.
Given a string containing only digits '0'-'9', write a function to determine if it's an additive number.
第一个数的范围: (n-1)/2
第二个数的范围: n-j>=i && n-j>=j-i
1 1 2 3 5 8
1 99 100 199
x1 = 100
x2 = 199
sum = 199
time : O(n^2)不确定
space : O(1)
* @param num
* @return
*/
public boolean isAdditiveNumber(String num) {
for (int i = 1; i <= num.length() / 2; i++) {
for (int j = 1; Math.max(i, j) <= num.length() - i - j; j++) {
if (isValid(i, j, num)) return true;
}
}
return false;
}
private boolean isValid(int i, int j, String num) {
if (num.charAt(0) == '0' && i > 1) return false;
if (num.charAt(i) == '0' && j > 1) return false;
String sum = "";
Long x1 = Long.parseLong(num.substring(0, i));
Long x2 = Long.parseLong(num.substring(i, i + j));
for (int start = i + j; start != num.length(); start += sum.length()) {
x2 = x2 + x1;
x1 = x2 - x1;
sum = x2.toString();
if (!num.startsWith(sum, start)) {
return false;
}
}
return true;
}
}