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2000. Reverse Prefix of Word #50

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F4NT0 opened this issue May 1, 2024 · 0 comments
Open

2000. Reverse Prefix of Word #50

F4NT0 opened this issue May 1, 2024 · 0 comments
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F4NT0 commented May 1, 2024

Given a 0-indexed string word and a character ch, reverse the segment of word that starts at index 0 and ends at the index of the first occurrence of ch (inclusive). If the character ch does not exist in word, do nothing.

For example, if word = "abcdefd" and ch = "d", then you should reverse the segment that starts at 0 and ends at 3 (inclusive). The resulting string will be "dcbaefd".
Return the resulting string.

Example 1:

  • Input: word = "abcdefd", ch = "d"
  • Output: "dcbaefd"
  • Explanation: The first occurrence of "d" is at index 3.
  • Reverse the part of word from 0 to 3 (inclusive), the resulting string is "dcbaefd".

Example 2:

  • Input: word = "xyxzxe", ch = "z"
  • Output: "zxyxxe"
  • Explanation: The first and only occurrence of "z" is at index 3.
  • Reverse the part of word from 0 to 3 (inclusive), the resulting string is "zxyxxe".

Example 3:

  • Input: word = "abcd", ch = "z"
  • Output: "abcd"
  • Explanation: "z" does not exist in word.
  • You should not do any reverse operation, the resulting string is "abcd".

Constraints:

  • 1 <= word.length <= 250
  • word consists of lowercase English letters.
  • ch is a lowercase English letter.
@F4NT0 F4NT0 added the Easy Easy Questions label May 1, 2024
@F4NT0 F4NT0 self-assigned this May 1, 2024
@F4NT0 F4NT0 added this to the May LeetCode milestone May 1, 2024
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