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reverseInteger.cpp
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reverseInteger.cpp
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// Source : https://oj.leetcode.com/problems/reverse-integer/
// Author : Hao Chen
// Date : 2014-06-18
/**********************************************************************************
*
* Reverse digits of an integer.
*
* Example1: x = 123, return 321
* Example2: x = -123, return -321
*
*
* Have you thought about this?
*
* Here are some good questions to ask before coding. Bonus points for you if you have already thought through this!
*
* > If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100.
*
* > Did you notice that the reversed integer might overflow? Assume the input is a 32-bit integer,
* then the reverse of 1000000003 overflows. How should you handle such cases?
*
* > Throw an exception? Good, but what if throwing an exception is not an option?
* You would then have to re-design the function (ie, add an extra parameter).
*
*
**********************************************************************************/
#include <stdio.h>
int reverse(int x) {
int y=0;
int n;
while( x>0 ){
n = x%10;
y = y*10 + n;
x /= 10;
}
return y;
}
int main()
{
printf("%d, %d\n", 123, reverse(123));
printf("%d, %d\n", -123, reverse(-123));
printf("%d, %d\n", 100, reverse(100));
printf("%d, %d\n", 1002, reverse(1002));
//overflow
printf("%d, %d\n", 1000000003 , reverse(1000000003 ));
printf("%d, %d\n", -2147447412 , reverse(-2147447412 ));
printf("%d\n", -2147447412 == reverse(-2147447412 ));
return 0;
}