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Use 4 bits for "visited", one for each wall.
0000 - 0000 == known(n-e-s-w) - walls(n-e-s-w)
http://blog.livedoor.jp/takayanagi_s_/archives/8915367.html
Could be useful in cases like:
o---o---o---o---o | | G | o o---o o---o | | ? | o o o o | | o o---o---o | S | o---o
Where ? would need to be visited in order to do the diagonal, when it would not be necessary.
?
The text was updated successfully, but these errors were encountered:
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Use 4 bits for "visited", one for each wall.
0000 - 0000 == known(n-e-s-w) - walls(n-e-s-w)
http://blog.livedoor.jp/takayanagi_s_/archives/8915367.html
Could be useful in cases like:
Where
?
would need to be visited in order to do the diagonal, when it would not be necessary.The text was updated successfully, but these errors were encountered: