Modified multiplication function. Base INT_MAX now works for multipli… #40
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Make sure to guard those calls to |
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…cation.
a *= 2 here 'a' would overflow if we change the base to INT_MAX. overflow can't occur when a < INT_MAX/2, therefore, the code was working only for base < INT_MAX/2. but now I have changed a *= 2 to a = (a+a)%base which is working for base INT_MAX. (only for multiplication)