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AGAGAXOOORRR#717.cpp
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AGAGAXOOORRR#717.cpp
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//Link to Problem: https://codeforces.com/contest/1516/problem/B
/** Hanabi?
** .
** .'
** .'
** /`-._'
** / /
** / /
** / /
** (`-./
** )
** ' .
** .'
** .'
** /`-._'
** / /
** / /
** / /
** (`-./
** )
** '
**/
//Kaicho Shirogane Miyuki
//Grieveous lady Shinomiya Kaguya
#include <bits/stdc++.h>
#define pb push_back
#define mp make_pair
#define fr first
#define sc second
#define MOD 1000000007
#define len(x) x.size()
#define min3(a, b, c) min(a, min(b, c))
#define max3(a, b, c) max(a, max(b, c))
#define all(v) v.begin(), v.end()
#define allr(v) v.rbegin(), v.rend()
#define alla(a,n) a, a + n
#define endstring std::string::npos
#define prtarr(n,len) {for(int i=0;i<len;i++) cout<<n[i]<<" "; cout<<"\n";}
#define prtset(n) {for(auto i:n) cout<<i<<" "; cout<<"\n";}
#define prtpair(n) {cout<<n.fr<<" "<<n.sc<<"\n";}
#define judge(a) {if(a) cout<<"YES"<<"\n"; else cout<<"NO"<<"\n";}
#define search(a,n) a.find(n);
#define Ataru main
using namespace std;
typedef long long int ll;
typedef unsigned long long ull;
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vpii;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<ull> vull;
typedef vector<pll> vpll;
typedef vector<vll> vvll;
typedef vector<vi> vvii;
typedef vector<string> vs;
using namespace std;
int inquire(int x,int y){
cout<<"? "<<x<<" "<<y<<endl;
int a; cin>>a;
return a;
}
const ll INF= 0x3f3f3f3f;
const ll MAX=1e5 + 5;
const ll LOG_MAX = 20;
ll cases,n;
int Ataru() {
ios_base::sync_with_stdio(false);
cin.tie(NULL) ; cout.tie(NULL) ;
//std::cout<<std::setprecision(2)<<std::fixed;
cin>>cases;
while(cases--){
cin>>n;
vll a(n);
ll mx=0;
ll ts=0; //XOR of every element in the given array
for(int i=0;i<n;i++){
cin>>a[i];
ts^=a[i];
}
int prefix=a[0];
bool exist=false;
for(int i=1;i<n;i++){
int mid=a[i];
for(int j=i+1;j<n;j++){
if(mid==prefix && mid==ts) exist=true;
mid^=a[j];
}
prefix^=a[i];
// prefix is the XOR of every element in the 1st segment
// mid is the XOR of every element in the middle segment
// ts is the XOR of every element in the last segment
}
judge(ts==0 || exist);
// if ts = 0, then no matter where we split the array the 2 portions will always equal
}
return 0;
}