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BinarySearchTreeIterator.java
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/*
Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST.
Calling next() will return the next smallest number in the BST.
Note: next() and hasNext() should run in average O(1) time and uses O(h) memory, where h is the height of the tree.
*/
import java.io.*;
import java.util.*;
public class BinarySearchTreeIterator {
public static class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) { val = x; }
}
public static class BSTIterator {
public Stack<TreeNode> st = new Stack<TreeNode>();
public BSTIterator(TreeNode root) {
while(root!= null){
st.add(root);
root = root.left;
}
}
/** @return whether we have a next smallest number */
public boolean hasNext() {
return !st.isEmpty();
}
/** @return the next smallest number */
public int next() {
TreeNode a = st.pop();
int res = a.val;
a = a.right;
while(a != null){
st.add(a);
a = a.left;
}
return res;
}
}
/**
* Your BSTIterator will be called like this:
* BSTIterator i = new BSTIterator(root);
* while (i.hasNext()) v[f()] = i.next();
*/
public static void main(String[] args) {
TreeNode root = new TreeNode(11);
TreeNode node2 = new TreeNode(6);
TreeNode node3 = new TreeNode(15);
TreeNode node4 = new TreeNode(4);
TreeNode node5 = new TreeNode(9);
TreeNode node6 = new TreeNode(12);
TreeNode node7 = new TreeNode(17);
TreeNode node8 = new TreeNode(1);
TreeNode node9 = new TreeNode(5);
TreeNode node10 = new TreeNode(7);
TreeNode node11 = new TreeNode(10);
root.left = node2;
root.right = node3;
node2.left = node4;
node2.right = node5;
node3.left = node6;
node3.right = node7;
node4.left = node8;
node4.right = node9;
node5.left = node10;
node5.right = node11;
node6.left = null;
node6.right = null;
node7.left = null;
node7.right = null;
node8.left = null;
node8.right = null;
node9.left = null;
node9.right = null;
node10.left = null;
node10.right = null;
node11.left = null;
node11.right = null;
BSTIterator i = new BSTIterator(root);
while (i.hasNext()){
System.out.println("The next smallest node:" + i.next());
}
return;
}
}