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diff --git a/leetcode/901-1000/0993.Cousins-in-Binary-Tree/README.md b/leetcode/901-1000/0993.Cousins-in-Binary-Tree/README.md
index 452ed5ecd..fac67ce16 100644
--- a/leetcode/901-1000/0993.Cousins-in-Binary-Tree/README.md
+++ b/leetcode/901-1000/0993.Cousins-in-Binary-Tree/README.md
@@ -1,28 +1,38 @@
 # [993.Cousins in Binary Tree][title]
 
-> [!WARNING|style:flat]
-> This question is temporarily unanswered if you have good ideas. Welcome to [Create Pull Request PR](https://github.com/kylesliu/awesome-golang-algorithm)
-
 ## Description
+Given the `root` of a binary tree with unique values and the values of two different nodes of the tree `x` and `y`, return `true` if the nodes corresponding to the values `x` and `y` in the tree are **cousins**, or `false` otherwise.
+
+Two nodes of a binary tree are **cousins** if they have the same depth with different parents.
+
+Note that in a binary tree, the root node is at the depth `0`, and children of each depth `k` node are at the depth `k + 1`.
 
-**Example 1:**
+**Example 1:**  
+
+![1](./1.png)
 
 ```
-Input: a = "11", b = "1"
-Output: "100"
+Input: root = [1,2,3,4], x = 4, y = 3
+Output: false
 ```
 
-## 题意
-> ...
+**Example 2:**  
 
-## 题解
+![2](./2.png)
 
-### 思路1
-> ...
-Cousins in Binary Tree
-```go
+```
+Input: root = [1,2,3,null,4,null,5], x = 5, y = 4
+Output: true
 ```
 
+**Example 3:**  
+
+![3](./3.png)
+
+```
+Input: root = [1,2,3,null,4], x = 2, y = 3
+Output: false
+```
 
 ## 结语
 
diff --git a/leetcode/901-1000/0993.Cousins-in-Binary-Tree/Solution.go b/leetcode/901-1000/0993.Cousins-in-Binary-Tree/Solution.go
index d115ccf5e..beb38ed9f 100644
--- a/leetcode/901-1000/0993.Cousins-in-Binary-Tree/Solution.go
+++ b/leetcode/901-1000/0993.Cousins-in-Binary-Tree/Solution.go
@@ -1,5 +1,35 @@
 package Solution
 
-func Solution(x bool) bool {
-	return x
+type TreeNode struct {
+	Val         int
+	Left, Right *TreeNode
+}
+
+func Solution(root *TreeNode, x int, y int) bool {
+	var (
+		xnode  *TreeNode
+		ynode  *TreeNode
+		xd, yd int
+	)
+	var dfs func(*TreeNode, *TreeNode, int)
+	dfs = func(fa, tree *TreeNode, dep int) {
+		if tree == nil {
+			return
+		}
+		if tree.Val == x {
+			xnode = fa
+			xd = dep
+		}
+		if tree.Val == y {
+			ynode = fa
+			yd = dep
+		}
+		dfs(tree, tree.Left, dep+1)
+		dfs(tree, tree.Right, dep+1)
+	}
+	dfs(nil, root, 0)
+	if xd != yd {
+		return false
+	}
+	return xnode != ynode
 }
diff --git a/leetcode/901-1000/0993.Cousins-in-Binary-Tree/Solution_test.go b/leetcode/901-1000/0993.Cousins-in-Binary-Tree/Solution_test.go
index 14ff50eb4..7921dae51 100644
--- a/leetcode/901-1000/0993.Cousins-in-Binary-Tree/Solution_test.go
+++ b/leetcode/901-1000/0993.Cousins-in-Binary-Tree/Solution_test.go
@@ -10,30 +10,57 @@ func TestSolution(t *testing.T) {
 	//	测试用例
 	cases := []struct {
 		name   string
-		inputs bool
+		tree   *TreeNode
+		x, y   int
 		expect bool
 	}{
-		{"TestCase", true, true},
-		{"TestCase", true, true},
-		{"TestCase", false, false},
+		{"TestCase1", &TreeNode{
+			Val: 1,
+			Left: &TreeNode{
+				Val:  2,
+				Left: &TreeNode{Val: 4},
+			},
+			Right: &TreeNode{Val: 3},
+		}, 4, 3, false},
+		{"TestCase2", &TreeNode{
+			Val: 1,
+			Left: &TreeNode{
+				Val:   2,
+				Right: &TreeNode{Val: 4},
+			},
+			Right: &TreeNode{
+				Val:   3,
+				Right: &TreeNode{Val: 5},
+			},
+		}, 5, 4, true},
+		{"TestCase3", &TreeNode{
+			Val: 1,
+			Left: &TreeNode{
+				Val: 2,
+				Right: &TreeNode{
+					Val: 4,
+				},
+			},
+			Right: &TreeNode{Val: 3},
+		}, 2, 3, false},
 	}
 
 	//	开始测试
 	for i, c := range cases {
 		t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
-			got := Solution(c.inputs)
+			got := Solution(c.tree, c.x, c.y)
 			if !reflect.DeepEqual(got, c.expect) {
-				t.Fatalf("expected: %v, but got: %v, with inputs: %v",
-					c.expect, got, c.inputs)
+				t.Fatalf("expected: %v, but got: %v, with inputs: %v %v %v",
+					c.expect, got, c.tree, c.x, c.y)
 			}
 		})
 	}
 }
 
-//	压力测试
+// 压力测试
 func BenchmarkSolution(b *testing.B) {
 }
 
-//	使用案列
+// 使用案列
 func ExampleSolution() {
 }